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What else can I help you with?
What is the definition of visionary?
Someone given to seeing visions or having fanciful theories.i
What is wrong with my deviantart?
1)Given that you haven't specified what you're experiencing with deviantART we are unable to answer your question. 2) LOL. REALLY DUDE? :L
What services does LCA provide for artists?
The LCA or the Lesher center for the Arts provides artists with a stage to set their talents afire in any aspect of art they may focus on. Grants are given out to various artists for them to continue their learning, funding is given also through Arts Access which is an outreach program giving artists who may face challenges in society help.
What does tattoo do to your body?
Tattoos can cause skin cancer to your body and ink poisoning to your skin ______________________________________________________________ The above given answer could not be any more incorrect. Tattoos do neither of these things.
What is Met Art's Koika's real name?
Her first name is Marie. Last name unknown. It's not Marie but Maria and the last name is usually given as Kuznetsova.
How do you find radius of curvature if focal length is given?
radius of curvature = 2Focal length
What is the focal length of a converging lens which produces a virtual image four time the size of the object the image being 15 cm from the lens?
Using the lens formula (1/f = 1/do + 1/di) and the magnification formula (m = -di/do) where m = -4, you can solve for the focal length (f). Given the object distance (do = -15 cm), you can calculate the focal length to be 10 cm.
What was the focal length when the radius of curvature was 0.70 m and index of refraction was 1.8?
The focal length of a lens is related to its radius of curvature and the index of refraction by the lensmaker's equation: [\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)] Given the radius of curvature (R = 0.70 , m) and the index of refraction (n = 1.8), you can calculate the focal length.
What is the power of a lens of focal length 40cm?
The power of a lens is given by the formula P = 1/f, where f is the focal length of the lens. Therefore, for a lens with a focal length of 40cm, the power would be P = 1/40 cm = 0.025 diopters.
What is the magnifying power of the lens if its focal length is 8cm?
The magnifying power of a lens is given by 1 + (D/F), where D is the least distance of distinct vision (typically 25 cm) and F is the focal length of the lens. Given a focal length of 8 cm, the magnifying power would be 1 + (25/8) = 4.125.
What would be the focal ratio of a telescope with a 5 aperture and a focal length of 25?
The focal ratio ( 'f' number ) is the ratio of focal length to diameter. For the numbers given in the question, assuming they're both in the same unit, this telescope is a 25/5 = f/5.
How do you calculate image position when given magnification of ian image by a concave miarror?
To calculate the image position when given magnification by a concave mirror, you can use the mirror equation: 1/f = 1/d_o + 1/d_i, where f is the focal length of the mirror, d_o is the object distance, and d_i is the image distance. Magnification, M, is also given by -d_i/d_o. By substituting the values of magnification and focal length into the mirror equation, you can solve for the image distance and then determine the image position.
If a telescope has an objective lens of 3 inches what is the focal length?
The size (diameter) of a lens does not determine its focal length. The amount of curvature of the lens does. Citing a diameter for a lens doesn't help us find the focal length. Lenses are ground to specifications that allow short or long focal length. The more curved the lens, the shorter the focal length. You can see this if we specify a given curvature and then start to "flatten" the lens. The focal length will get longer and longer as the lens is flattened. When the lens is flat (has to curvature) the lense has an infinite focal length, just like a piece of flat glass.
Power of lens is plus 1.5 d find focal length?
The focal length of a lens can be calculated using the formula: ( \text{focal length (cm)} = \frac{1}{\text{power of lens (diopters)}} ). Substituting the given power of ( +1.5 \text{ D} ), we get ( \text{focal length (cm)} = \frac{1}{1.5} = 0.67 \text{ cm} ).
What is the magnification of a lens with a focal of 2 in?
The magnification of a lens depends on the object distance and image distance from the lens. The magnification formula is given by M = -image distance/object distance. Without knowing the object distance, it is not possible to calculate the magnification of the lens with a focal length of 2 inches.
The depth of field in a photograph is controlled by the?
Depth of field on a camera is controlled by the aperture. The aperture is basically the size of the opening in the lens. A large aperture (or opening) creates a shallower depth of field and a small aperture creates a greater depth of field. Aperture, along with shutter speed, determine how much light goes into the camera. The size of the aperture is indicated by the f/stop number. The numbers usually range from about f/1 to around f/64. The smaller the number is, the larger the aperture is and the shallower the depth of field, meaning less space is in focus.Additional AnswerDepth of field is also affected by the focal length of your camera's lens. For any given aperture, longer focal length lenses (telephoto lenses) have a much narrower depth of field than a standard lens, and shorter focal length lenses (wide-angle lenses) have a much wider depth of field than a standard lens.
What will be the power of convex lens having a focal length is 50 cm?
The power of a lens is given by the formula P = 1/f, where f is the focal length in meters. Converting 50 cm to meters, we get f = 0.5 m. Therefore, the power of a convex lens with a focal length of 50 cm is P = 1/0.5 = 2 diopters.
