To calculate the time it would take to heat 200 gallons of water by 180 degrees using a 600 Btu water heater, you would first determine the total heat required: Calculate the heat energy required: Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the temperature change. Then, calculate the time required to heat the water using the formula: Time = Q / power of the heater. These calculations will give you an estimate of the time needed to heat the water based on the specific heat capacity of water and the power of the heater.
That depends on the starting temperature of the cold water and the starting temperature of the hot water.
A watt is a unit of power: what is required is probably the amount of energy - which is measured in joules.
Great question except 1- What is the BTUH being used 2- What is the ambient temperature 3- Latient heat?
100 degrees celsius are equal to 212 degrees fahrenheit.
Water boils at 100C (or 212F) at sea level.
Water boils at 100 degrees Celsius or 212 degrees Fahrenheit.
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
The Tiny Titan is 2.5 gallons.
answer: 7680 btu 1 gallon= 8 lb 130F-50F=80F 12G*8LB*80F=7680 BTU
170o