Its more about water volume and filter area. We have a 100,000 gallon pool that uses 180 square feet of filter area - these consume 25 pounds of DE every time we backflush and recharge the filters.
Assuming your pool is 5 feet deep on average you only have 3000 cubic feet of water which is about 23,000 gallons. So you would need roughly 6 or 7 pounds of DE. Of course if your pool has more water then you need more DE. Your filter manufacturers should tell you how much DE you need.
A 28-foot round pool filled with 4 feet of water would contain about 18,500 gallons.
About 18,402 gallons.
20000
To calculate the square footage of a round pool, you can use the formula for the area of a circle: A = πr². For a 28-foot round pool, the radius (r) is 14 feet. Therefore, the area is approximately A = π × (14)² ≈ 615.75 square feet.
I do not have any water in your pool. You may have some but not me!
28 is the diameter of the pool and 4 is the height (depth). 1 cubic foot is approx. 7.48 gallons. A round swimming pool is a cylinder. So: pi x (28/2)2 x 4 = 2463 cubic feet, multiply by 7.48 = 18423.24 gallons
That all depends on how deep the water has to be, which the question neglects to specify.
28 or 30 mil
To calculate the volume in gallons of a round pool, do the following calculation: diameter x diameter x depth x 5.9 Example: 28ft x 28ft x 4ft x 5.9 = 18,502.4 gallons
3.14 x28 x 28 /4 x 4 x 7.48gals/ cu ct = 18, 400 gallons
This pool can hold a maximum of about 18,420 gallons of water.
If the pool is 28 feet wide, you'd have to walk around the outside 60 times to equal one mile of distance.