i found two .22 semi auto rifles marked Springfield and Speingfield Stevens model 87 A on Auction Arms . the asking price was between $65 and $145. i have a Wards Western Field model 87 that appears to be identical to these two and i know it to be over 50 years old. i am 51 and this rifle belonged to my father and it was in his home for as long as i can remember. i should have asked him when and where he acquired it but never did. if your 87N is a tube fed .22 repeater it may be a later production version or if it is a clip fed repeater it could be a contemporary. look on AA under rifles and search for Springfield. this may help you determine if your rifle is a varient of the Model 87A
AnswerThe Springfield name was used by Stevens/Savage from about 1920 to 1948. According to the Blue Book, the 87 series was made from 1938 to 1945. Value is probably $75 to $150.$55
SevenHundred
Made in 1902
Your springfield model 1898 was produced in 1899.
Yes, here's the proof.Let's start out with the basic inequality 81 < 87 < 100.Now, we'll take the square root of this inequality:9 < √87 < 10.If you subtract all numbers by 9, you get:0 < √87 - 9 < 1.If √87 is rational, then it can be expressed as a fraction of two integers, m/n. This next part is the only remotely tricky part of this proof, so pay attention. We're going to assume that m/n is in its most reduced form; i.e., that the value for n is the smallest it can be and still be able to represent √87. Therefore, √87n must be an integer, and n must be the smallest multiple of √87 to make this true. If you don't understand this part, read it again, because this is the heart of the proof.Now, we're going to multiply √87n by (√87 - 9). This gives 87n - 9√87n. Well, 87n is an integer, and, as we explained above, √87n is also an integer, so 9√87n is an integer too; therefore, 87n - 9√87n is an integer as well. We're going to rearrange this expression to (√87n - 9n)√87 and then set the term (√87n - 9n) equal to p, for simplicity. This gives us the expression √87p, which is equal to 87n - 9√87n, and is an integer.Remember, from above, that 0 < √87 - 9 < 1.If we multiply this inequality by n, we get 0 < √87n - 9n < n, or, from what we defined above, 0 < p < n. This means that p < n and thus √87p < √87n. We've already determined that both √87p and √87n are integers, but recall that we said n was the smallest multiple of √87 to yield an integer value. Thus, √87p < √87n is a contradiction; therefore √87 can't be rational and so must be irrational.Q.E.D.The question asks if 87 is rational, not √87. 87 is rational because it can be expressed as the ratio of two integers i.e. 87 = 87/1.
made by Colt 1912 for US Navy. not unusual to see springfield slide on a Colt frame
about 1886
The Stevens "Springfield" Model 83 was manufactured from 1935 to 1939. Value is between $40 to $75.
The value of a Springfield 20 gauge pump shotgun would actually depend on a number of factors. Some of these factors would be the age and the condition of the shotgun.
I can tell you the Springfield name was discontinued in 1948. Value would be from around 250.00-350.00 assuming it's in very good to excellent shape.
it's colt made in 1918. if your slide reads 'springfield' then someone put a springfield slide on the colt frame. that is not unusual................
made 1919. value would depend on overall condition