I hope there is a double "L" on that name. C.G.Bonehill was a manufacturer in Birmingham, England, 1872-1965. If there really is only one "L", then your gun is probably a Belgian knockoff. Either way, its value will be directly related to how well it looks over the mantle, usually around $125-$150. Maybe a bit more since it is marked with the maker's name instead of a store brand.
pump gun how old is it
No more than 100 USD
100-400 USD
0-550 uSD
No way to answer without the sn and a detailed description.
Western field 12 gauge single shot shotgun serial #82719 x G...age and value/
50-100 USD
Bolt action made by Savage/Stevens. $75-$125.
50-5000 USD depending on specifics.
You need the services of an appraiser
The Second Mean Value Theorem for Riemann integrals states that if ( f ) and ( g ) are continuous functions on the closed interval ([a, b]) and ( g ) is non-negative and integrable, then there exists a point ( c \in [a, b] ) such that: [ \int_a^b f(x) g(x) , dx = f(c) \int_a^b g(x) , dx. ] Proof: Define ( G(x) = \int_a^x g(t) , dt ). Since ( g ) is continuous, ( G ) is differentiable and ( G(a) = 0 ). By applying the Mean Value Theorem to ( G ) over ([a, b]), we find a ( c \in [a, b] ) such that: [ G(b) = G'(c)(b - a) = g(c)(b - a). ] Thus, we have: [ \int_a^b g(x) , dx = G(b) = g(c)(b - a), ] which leads to the conclusion that: [ \int_a^b f(x) g(x) , dx = f(c) \int_a^b g(x) , dx. ]
100-10000 USD depending on specifics