How many gallons of water in 48x21x18 ins fish tank?

Answer 1

We will assume the tank is cylindrical with a circumference of 48 inches and a height of 10 feet. First, you must ensure that units are consistent, so you will have to convert inches to feet or feet to inches. Let's convert feet to inches. So, 10 feet = 120 inches, since there are 12 inches to the foot. Second, we must calculate the radius, r, of the cylinder by dividing the circumference by (2*Pi). So 48 / (2*Pi) = 7.64 inches. Third, we use the volume of a cylinder to calculate the volume of the tank in cubic inches: V = (Pi)r2h, where Pi = 3.141, r is the radius of the cylinder, and h is its height. Therefore, we have V = 3.141 * 7.642 * 120 = 22001.58 cubic inches. Last, we convert cubic inches to gallons. Since there are 231 cubic inches to the gallon, we divide our answer in the third step by 231. So, 22004.8 / 231 = 95.24 gallons. The above process used the familiar formula for volume. To use it, it was necessary to calculate the radius from the given information, namely, the circumference. We could have skipped that step had we used another simple, albeit less familiar formula. The volume of a cylinder is simply the area of its base times its height. And the area of the base can be calculated directly from its circumference: A = C2/(4*Pi). So, V = h * C2/(4*Pi) = 120 * 482 / (4 * 3.141) = 22001.58 cubic inches. We still need to divide by 231 to get 95.24 gallons.

Answer 2

48x27x19=24624 cubic inches of water

or

106.6 gallons of water

Answer 3

volume of water =21 X 14 X40

=11760 inch ^3

Answer 4

That commonly referred to as a 75 Gallon Fish tank.

Answer 5

52.36 gallons if filled to capacity.