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Put 5 sheep in each of three small pens... THEN - build a larger pen enclosing the three smaller ones. The smaller pens each have an odd number of sheep in them (5 in each) - and the large pen has a total of 15 sheep enclosed within it !

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10y ago
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Bridget Makuta

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1y ago
Why use an odd number of ewes
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14y ago

You don't need to use all 35 pigs. You only need to ensure that there is an uneven number of pigs in each of the four pens. You could, for example, put 1 pig in each pen and therfore solve the problem.

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11y ago

1st pen- 3 pig

2nd pen- 3 pigs

3rd pen- 3 pigs

4th pen- It is around the 1st,2nd and 3rd pen.

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12y ago

At least one pen is fully contained within another.

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14y ago

No. 21 pigs in each of the 4 pens is 21 times 4 which equals 84 pigs. 84 is an even number.

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15y ago

snotpossible

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Q: If 15 pigs are put in 4 pens how can there be an odd number of pigs in each pen?
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