100% because BB is dominant over bb and all the crosses make Bb
depends if the black fur gene is dominant..
if it is...
then yu would cross BB with bb making all heterozygous genotypes(Bb)
therefore, having all possible offspring with black fur
so theres a 100% probability of offspring with black fur(:
Homozygous means both alleles are the same. Hence, crossing a homozygous brown (say BB) with a homozygous white (say ww) will produce heterozygous Bw offspring--there's no alternative to this. Since brown is dominant, all the offspring will be brown.
It gets fun in the next generation. If you mate a Bw male with a Bw female from another set of parents, you have 25 percent chance of BB, 50 percent of Bw and 25 percent of ww--or 75 percent chance the offspring will be brown. You get a 50-percent chance of brown ones if you cross one of these Bw guinea pigs with a ww guinea pig--we know one side WILL contribute a white gene, so you'll get either Bw or ww offspring.
None. Chickens have feathers not fur.
Now to color. The male usually determines color so without that information it is hard to answer with any authority.
In most crosses if the male is black and the hen is white you will get some black chicks and all will have white/black variations.
If the male is white and the hen is black you will get some all white with others showing black and white.
If the breed is Leghorn, even if the rooster is black you will get mostly white chicks with some throwbacks in red and buff.
100% because BB is dominant over bb and all the crosses make Bb
If Bb also gives the guinea pigs black fur then 3 in 4 or 75% of them will be black. If only BB does then only 1 in 4 or 25% will be born with black fur.
The chance is 25%.
4 offsprings
Assuming black allele exhibits complete dominance and the white allele is recessive, the genotype is Bb.
A rough-coat is recessive for this trait. Thus a rough-coat is heterozygous and a smooth-coat is homozygous.
Basically a crossbreed
You could try breeding it with a homozygous recessive partner (hh) Lets assume that you breed the original mystery rabbit with an hh recessive partner, and they have 10 offspring. If the original rabbit is homozygous dominant, it would be HH + hh, which would give all 10 the offspring Hh genotypes, which would give them the dominant hair color. If it was heterozygous dominant, it would be Hh + hh, which would lead to either Hh or hh offspring. This means that in theory, 5 would be dominant colored while the other 5 would not be.
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
The offspring will look more like the mom but they will have mid hair.
4 offsprings
Assuming black allele exhibits complete dominance and the white allele is recessive, the genotype is Bb.
depends on the two guinea pigs genotypes. could be anywhere from 75 to 100 percent.
This is probably the result of the brown genes being dominant and the white genes being recessive. this is correct.
Abyssinian
A rough-coat is recessive for this trait. Thus a rough-coat is heterozygous and a smooth-coat is homozygous.
No, guinea pigs and possums can't be crossed. Guinea pigs are Eutherians while possums are marsupials. Species as far apart as these simply can't be crossed.
Nope.
Cross between homozygous black rough (BBRR) guinea pig and homozgous white smooth guinea pig (bbrr) produced black and rough animals in F1 generation.
Basically a crossbreed