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What is the F1 and F2 genotypic and phenotypic ratios of a cross of a smooth white guinea pig with a homozygous rough yellow guinea pig?
some important facts:
This is a lot of info, but if you take it slowly and step by step, you will start to understand how it works.....
-Rough hair is dominant to smooth hair.
-pure breeding yellow crossed with a pure breeding white always = a cream color SO that means that this is incomplete dominance. (which means that neither yellow or white is dominant). Cream color will always appear as YW (or CyCw -for color yellow and color white).
-Homozygous means that the rough yellow can only be RRYY (and not RrYY-that would be heterozygous).
so...
smooth white =rrWW and homozygous rough yellow =RRYY
#1) Find the possibilities of genes that each parent could contribute by taking the 1st R (or r) of each parent and matching it to the 1st W or Y (of the same parent)and writing it down. Then you take the first R (or r) and match it to the second W or Y. Next match the 2nd R (or r) to the 1st W or Y and then the 2nd R (or r) to the 2nd W or Y. So for the smooth white, you would have the possibilities: rW, rW, rW and rW. For the homo rough yellow: RY, RY, RY & RY.
2). make a punnette square with all of the smooth white possibilities at the top and all of the rough yellow on the side. (I won't explain how to do the Punnette square as you are probably familiar with that). The results that you get are all of the possibilities that can exist in the next generation. From crossing those, you will get that all F1 (first generation) offspring would be rough and cream colored (phenotype) and the genotype is: RrYW. The phenotypic ratio is 1:0 (it is 16:0 because there is 16 rough, cream and 0 of anything else, but you reduce it to lower terms).
3). To get 2nd generation, you would cross one of the offspring with the other, which would be RrYW X RrYW. You would repeat the step #1 above to get the possibilities of genes that could be contributed. you will have from one parent: RY, RW, ry, and rw. In this particular case, you will have the same possibilities from the other parent (since they are the same).
4). Make a Punnette Square with the possibilities above across the top and across the left side. You will get 16 results: RRYY, RRYW, RrYY, RrYW, RRYW, RRWW, RrYW, RrWW, RrYY, RrYW, rrYY, rrYW, RrYW, RrWW, rrYW, rrWW.
5). From these results, you get:
Rough, Yellow: 3
Rough Cream: 6
Rough White: 3
Smooth Yellow: 1
Smooth Cream: 2
Smooth White: 1
What else can I help you with?
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The proportion of sexes varies in both directions when the ratios were determined with random numbers. In other words, it's a 50/50 chance that a cow will have a heifer calf or a bull calf.
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The internal reflux ratio is the ratio of the liquid returned as reflux to the distillate product inside the column, while the external reflux ratio is the ratio of the liquid refluxed back to the column to the distillate product taken out of the column. These ratios are related as the sum of the internal and external reflux ratios is equal to the total reflux ratio, which can affect the separation efficiency and energy consumption in a distillation column.
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The Border Collie is known to have one of the largest brain-to-body ratios among dogs. They are highly intelligent and excel in various tasks, making them popular choices for canine work such as herding and agility competitions.
This animal in austraulia outnumbers humans 7 to 1 and 14 to 1 in new zealandwhat animal is it and does it produce 50 of the worlds total?
The animal is the sheep. They outnumber humans in Australia and New Zealand at the given ratios. Sheep do not produce 50% of the world's total.
Are phenotypic ratios are always the same as genotypic ratios?
No, phenotypic ratios are not always the same as genotypic ratios. Phenotypic ratios are based on the physical appearance of individuals, while genotypic ratios are based on the genetic makeup of individuals. Various factors such as dominance, incomplete dominance, and gene interactions can result in differences between phenotypic and genotypic ratios.
Predict the genotypic and phenotypic ratios in the offspring if the mother is bold and the father is not bold?
To predict the genotypic and phenotypic ratios, we first need to establish the alleles for boldness. Let's assume boldness (B) is dominant and non-boldness (b) is recessive. If the mother is bold, she could be either homozygous (BB) or heterozygous (Bb). If the father is not bold, he is homozygous recessive (bb). If the mother is BB, all offspring will be bold (100% phenotypically bold, BB genotype). If the mother is Bb, the offspring will have a genotypic ratio of 1 BB: 1 Bb (100% bold), resulting in a phenotypic ratio of 100% bold. In summary, regardless of the mother's genotype, all offspring will exhibit the bold phenotype.
What is the expected genotypic ratios for di-hybrid cross and mono-hybrid cross?
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
In aquirrelsblack fur is recessive to grar fur show the genotypic and phenotypic ratios of a cross between a heterozygous gray squirrel with a black squirrel?
The genotypic ratio would be 1:2:1 (1 BB, 2 Bb, 1 bb) and the phenotypic ratio would be 3:1 (3 gray squirrels : 1 black squirrel).
Which genotype is used in a test cross?
In a test cross, one individual with a dominant phenotype but unknown genotype is crossed with a homozygous recessive individual. The genotype of the individual with the dominant phenotype can then be inferred based on the phenotypic ratios of the offspring.
Predict the genotypic ang phenotypic ratios in the offspring if the mother is bald and the father is not bald. perform a cross using a punnett square?
Assuming baldness is a trait determined by a dominant allele (B for bald, b for not bald), if the mother is bald (genotype BB or Bb) and the father is not bald (genotype bb), the offspring's genotypic ratio will depend on the mother's genotype. If the mother is BB, all offspring will be Bb (bald), resulting in a phenotypic ratio of 100% bald. If the mother is Bb, the genotypic ratio will be 1 Bb : 1 bb, leading to a phenotypic ratio of 50% bald and 50% not bald.
Why would it be important to know the possible genotypic and phenotypic ratios of different genetic crosses?
Knowing the possible genotypic and phenotypic ratios of different genetic crosses is crucial for predicting the inheritance patterns of traits in offspring. This information aids in understanding how certain traits may be expressed in future generations, which is important for fields like agriculture, medicine, and conservation. Additionally, it can inform breeding strategies, genetic counseling, and the study of hereditary diseases. Overall, it enhances our comprehension of genetic variability and its implications in various biological contexts.
To perform a testcross scientists cross an organism with an unknown genotype with what kind of organism?
To perform a testcross, scientists cross the organism with an unknown genotype with a homozygous recessive organism. This allows researchers to determine the unknown genotype based on the phenotypic ratios observed in the offspring.
How does the Key Term hybrid apply to a mono hybrid cross?
In a monohybrid cross, the term "hybrid" refers to the offspring resulting from the mating of two individuals with different alleles for a single trait. This cross typically involves one parent that is homozygous for one allele and another that is homozygous for a different allele, producing heterozygous offspring. These hybrids exhibit a combination of traits from both parent organisms, allowing for the study of inheritance patterns and dominant versus recessive traits. The resulting genotypic and phenotypic ratios can provide insights into Mendelian inheritance.
How did Mendel experimental result compare to the theoretical genotypic ratios?
Mendel's experimental results closely aligned with the theoretical genotypic ratios predicted by his laws of inheritance. In his pea plant experiments, he observed a 3:1 phenotypic ratio in the F2 generation for dominant and recessive traits, which corresponded to a 1:2:1 genotypic ratio among the offspring. These findings confirmed Mendel's hypotheses about the segregation and independent assortment of alleles, establishing a foundational understanding of genetic inheritance. Overall, Mendel's empirical observations supported and validated the theoretical expectations of Mendelian genetics.
When trying to find an unknown genotype you must perform a?
Perform a test cross. Cross the organism with an organism with a homozygous recessive genotype and use the phenotypes of the offspring and a Punnett square to figure out the unknown genotype.
How can you do a genetic cross to identify the P genotype?
The genotype of the P (parent) generation can be done by crossing an offspring from the F1 (first filial) generation with one of the gametes from the P generation and then calculating the genotypic and phenotypic ratios. Such an experiment is called a back cross
