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The net effective resistance of six 3-ohm resistances in series is (3 + 3 + 3 + 3 + 3 +3) = 18 ohms.

Current = E/R = 9/18 = 0.5 Amp.

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Q: A student connects six 3-ohm light bulbs in series to a 9-volt battery The total circuit current is what?
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