A vehicle travels approximately 1.5 ft per second for each mile per hour. 25 x 1.5 = 37.5. Add to that the average human response time to react to stimuli and apply the brake (1.5 sec again) = 56.25 ft before the vehicle begins to stop.
Braking on most surfaces slows you 15 feet per second, per second of braking.
37.5 fps to 0 fps = 2.5 sec to stop
(37.5 fps/2) x 2.5 sec = 46.875 ft braking distance +56.25 reaction distance
= 103.125 ft between recognition of a danger and your vehicle stopping.
Add to that the braking efficiency of the vehicle. You can also account for the drag coefficient of the pavement and grade (.7 to .8)but that is usually a negligible amount unless you are doing serious traffic crash reconstructions.
228 feet
One foot. Your foot on the brake. Sorry, I couldn't resist. That answer is absolutely correct
a round 62 feet
One foot planted firmly on the brake pedal
That depends on the mass of the car, and the composition and condition of the pavement.
You should memorize 60 mph = 88 feet per sec. Then (25 mph)/(60 mph)*(88 feet/sec) = 36.6666.... feet per second
Stopping distance for a car travelling at 25mph is 38 feet, you would need to add a reaction time (the time between when you see the need to stop and you react by appling the brakes)
228 ft
2,200 feet per second is 1,500 mph
15 mph = 22 feet per second
40 mph = about 58.6 feet per second.
350 feet per second = 238.64 mph
69 mph is 101.2 feet per second.
55 mph = 80.6666 feet per second
1,000 mph = 1,466.66 feet per second
240 mph = 352 feet per second.
132 feet per second at 90 mph.
1.46 feet per second at 1 mph.
125 mph = 183.33 feet per second.
(19 (mph) * 1760 * 3) / 3600 = 27.86 feet per second (approx) > mph>yards per hour>feet per hour>feet per second