Mg+ 2HNO3-->Mg(NO3)2 + H2
Products are Magnesium nitrate and Hydrogen gas.
Mg(s)+N2(g)=Mg3N2 Number of atoms = Mg 1 Mg3 N2 N2 Not blanced To balance place 3 in front of Mg on the left. 3Mg(s)+N2(g)=Mg3N2(s) Number of atom = Mg 3 Mg3 N2 N2 Balnaced
Mg3N2 + 3H2O ----> 3Mg(OH)2 + 2NH3
You need to reduce the coefficients to their least common denominator. ^_^
Mg + N ---> MgN
3 Mg (s) + N2 (g) -->Mg3 N2
When burning magnesium in nitrogen, magnesium nitride is formed.
3Mg + N2 ---> Mg3N2
Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
Mg3N2 + 6 H2O = 3 Mg(OH)2 + 2 NH3
m=mc^2
There is no equation in the question, only two pair of two reactants.
MgBr2 + Cl2 --> MgCl2 + Br2
Mg + 2HCl --> MgCl2 + H2 Magnesium plus hydrochloric acid equals magnesium chloride plus hydrogen gas.
2Mg + I2 ----> 2MgI
2Mg + 0 2 = 2MgO
H2o+no2
3h2 + n2 ==> 2nh3
This equation is:Mg + H2SO4 = MgSO4 + H2
You would start with writing the equation out, ensuring the compounds are balanced and neutral: MgO + H2O -----> Mg(OH)2 In this case, the equation is already balanced - there are two hydrogen, one magnesium, and two oxygen atoms on each side.
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
There is no equation in the question, only two pair of two reactants.
Mg + 2HCl --> MgCl2 + H2
MgBr2 + Cl2 --> MgCl2 + Br2
Mg + 2HCl --> MgCl2 + H2 Magnesium plus hydrochloric acid equals magnesium chloride plus hydrogen gas.
2H2 + 2NO --> 2H2O + N2
2Mg + I2 ----> 2MgI
4H2 + N2 --> 2H4N+