C program code for concatenation of string?

Answer 1

Here You Are :

void String_Concate(char *Arr1, char *Arr2)

{

int r=0;

int c = String_Length(Arr1);

int x,p;

for(int i=0;Arr1[i];i++)

{

if((Arr1[i]== 32)(Arr1[i]=='\0'))

{r= i;

break;}

}

for(x = r,p =0;x<=c + String_Length(Arr2);x++,p++)

{

*(Arr1 + x) = *(Arr2 + p);

}

}

Have A nice Day

Answer 2

// stores srcL + srcR into dest

// NOTE: dest must be at least as large as srcL + srcR

void strConcat(const char* srcL, const char* srcR, char* dest) {

const int lengthL = strLength(srcL);

const int lengthR = strLength(srcR);

// copy srcL into front of dest

int i;

for(i = 0; i < lengthL; ++i) {

dest[i] = srcL[i];

}

// copy srcR into the rest of dest

for(i = 0; i < lengthR; ++i) {

dest[lengthL + i] = srcR[i];

}

dest[lengthL + i] = '\0';

}

// returns the number of characters in str

int strLength(const char* str) {

int length = 0;

// take advantage of the fact that all strings MUST end in a null character

while( str[length] != '\0' ) {

++length;

}

return length;

}