The water and pot(/) have a temperature increase of 100-25 degrees C that is 75 degrees. the formula Q=mass * SH* change in temperature can be used for both the water and the steel pot Hence for steel pot Q=510 j/kg/degC*.5kg*75Deg C=19125 joule. For water SH=4187 j/kg/C QW= .45*4187*75=141311 joule total heat (neglecting changes and losses to get the water to 100 deg C is 160436 joule or 160.4 kjoule. Note this does not boil the water it only raises the temperature to 100 degrees C. to boil the water requires approximately a futher 1250 kJ
No. Metals have a relatively low specific heat.
The specific heat capacity of sodium is 28,23 J/mol.K at 25 0C.
-0.16
because of high specific heat capacity.
.44 btu/lb
-25degrees
-25degrees
A calorimeter can be used to calculate specific heat capacity.
Please be more specific...
Specific heat capacity(q) is the amount of heat needed to raise a tamperature of a body with mass of 1kg by 1K or 1 decree celcius. The formuale to calculate it is c(specific heat capacity) = Q/mass x change in temperature.
specific heat capacity
The specific heat capacity of polyester is 2.35degrees
that will be true
The heat capacity of anything is the amount of energy required to raise the temperature of 1 g of the substance by 1 degree Celsius. You can use this fact to calculate the heat capacity of a wort.
sand have low specific heat capacity.
5120 j/g k is the specific heat capacity
No. Metals have a relatively low specific heat.