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The water and pot(/) have a temperature increase of 100-25 degrees C that is 75 degrees. the formula Q=mass * SH* change in temperature can be used for both the water and the steel pot Hence for steel pot Q=510 j/kg/degC*.5kg*75Deg C=19125 joule. For water SH=4187 j/kg/C QW= .45*4187*75=141311 joule total heat (neglecting changes and losses to get the water to 100 deg C is 160436 joule or 160.4 kjoule. Note this does not boil the water it only raises the temperature to 100 degrees C. to boil the water requires approximately a futher 1250 kJ

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Q: Calculate the heat given to a 500g steel containing 450g of water to raise the temp from 25degrees Celsius to 100The specific heat capacity of steel.510 Steel and water have the same temp changes?
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