no..... The battery with lower voltage will consume power from the higher one...
Yes. this is commonly done. However, performance is better and costs lower if you use the proper diode for production devices. Absolutely NOT. For the same reason that capacitor cannot be added in series to withstand higher voltage. Not all components are made equally Supposed that you have two diodes rated at 100v add them in series makes 200v not quite if one leaks more then the other unequal voltage will results blowing them up. There is a simple solution add a parallel high resistor across each component to equalize the voltage then YES it is possible to add them in series
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
Ideally all three phase currents will be equal. There may exist some voltage imbalance from the power source, which will result in unequal currents.
A balanced three phase load is where the current flowing in all three phases of the load are reasonably close to each other.Another answerWhen the voltage and measured current draw do not deviate by more than 2 percent under load.AnswerA balanced three-phase load is one in which each of the three loads is identical in all respects (magnitude and phase). Further to the first answer, the three line currents must not all be 'reasonably close', they must be identical -i.e. the same value and phase relationship.
Common Mode gain is the response of a circuit where the input changes relative to some common point, such as ground. A single transistor amplifier is an example. An op-amp can also be an example, if one input is grounded.Differential Mode gain is the response of a circuit where the input is measured across two pins, and the difference between those two pins controls the output, rather than the common mode value of those pins relative to ground. An op-amp in balanced or bridge mode is an example.One way to verify/understand this is to take a properly designed op-amp, connect the two inputs together, and drive them together relative to ground. A properly balanced system will exhibit little or no response on the output. Note: This is also true for AC, so a typical test includes both DC and AC response. In the AC test, imbalance often results from unequal capacitance, whereas DC imbalance results from unequal resistance.
If two ideal sources of unequal voltage are connected in parallel the higher voltage will provide a majority of the current (a two percent difference in voltage would provide an additional 5% of the current) and (in the case of batteries) the larger would provide charging current, quickly draining it.
quadrilateral
trapezium :)
A trapezium has two parallel sides (of unequal length) and two non-parallel sides.
A trapezium (US) has no sides parallel, while a trapezoid has one set of unequal parallel sides.
quadrilateral
They are different and unequal.
it is a trapezium
The trapezoid (UK trapezium) has only 1 pair of unequal parallel sides.
yes ,they can be connected ,then they both will drive the current through that resistance ,the current through that resistance will be the sum of currents due to each individual source taking only one at a time (use superpositon theorem)
It cannot. A trapezium is a quadrilateral that has one pair of parallel but unequal sides and another pair of non-parallel sides. A parallelogram has two pairs of parallel and equal sides.
A trapezium (has only one pair of unequal parallel lines).