answersLogoWhite

0

Can you use a 13A power cord in place of a 12A power cord?

Updated: 8/20/2019
User Avatar

Wiki User

10y ago

Best Answer

As long as the power cord has greater capacity than the load it is supplying, then it can be used. In some instances this might not work as the cap also has to match the receptacle that it is connected into.

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Can you use a 13A power cord in place of a 12A power cord?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you simplify 12a plus a?

13a


Can you simplify this expression 12a plus a?

13a


13a - 15b -a plus 2b?

Re-ordering it : 13a - a -15b + 2b = 12a - 13b


How do you solve a to te second power subtracting 13a plus 22?

a2 - 13a + 22 You're looking for factors of 22 that add up to 13. (a - 2)(a - 11) a = 2, 11


What is the coefficient of the term 13a in the expression 13a plus 6b?

14


What is 2a2-13a plus 15 equal when factored?

2a2 - 13a + 15 = (2a - 3) (a - 5)


What is the power of a d size battery?

The power of a d size battery is usually 13A but it all depends upon the chemistry of battery but these batteries are usually made to support small physical devices.


How do you simplify 6a2 - 6ab plus 7a2?

6a^2 - 6ab + 7a^2 = 13a^2 - 6ab = a * (13a - 6b)


Will a 16A 250v plug work with a 13A 240 v travel adaptor?

Yes provided the adaptor, or the plug that is plugged in, has a 13A fuse.


What is the value of a in 13a - 6 plus a equals 5a plus 3 plus 3a?

13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2


What are the answers to a puzzle of tiny things?

10a=pathogenic 11d=lacticacid 1d=lyticcycle 2d=endospores 3d=host 4d=virus 7d=decomposers 8d=cocci 9d=spiralla 15d=consumer 6d=fission 5a=nitrogenfixing 12a=prokaryote 13a=antibiotics 14a=vaccine 16a=bioremediation


How do you find the sum or difference of (5a2 plus 6a plus 2)-(7a2-7a plus 5)?

Combine like terms, adding/subtracting the coefficients: (5a² + 6a + 2) + (7a² - 7a + 5) = (5+7)a² + (6-7)a + (2+5) = 12a² - a + 7 (5a² + 6a + 2) - (7a² - 7a + 5) = (5a² + 6a + 2) + (-7a² + 7a - 5) = (5-7)a² + (6+7)a + (2-5) = -2a² + 13a - 3