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# Divide x to the 5th power by x to the 2nd power?

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View Full Interview# What is the integral of tan squared x cosine to the 5th power x dx?

Since you did not specify any limits of integration, I assume you are looking for the indefinite integral of this expression: tan2(x)cos5(x) with respect to x (dx). Using th…e following identity: tan(x) = sin(x) / cos(x) The original expression can be rewritten as: (sin2(x) / cos2(x))cos5(x) Which further simplifies to: sin2(x)cos3(x) Which can be expanded to: sin2(x)cos2(x)cos(x) Using the identity: sin2(x) + cos2(x) = 1 which implies: cos2(x) = 1 - sin2(x) which makes the expression from above able to be simplified into: sin2(x)(1 - sin2(x))cos(x) From here, you can use u-substitution by using the substitution: u = sin(x) du = cos(x) dx => dx = du/cos(x) So after u substitution: int(sin2(x)(1 - sin2(x))cos(x)) dx becomes: int(u2(1-u2)) du int(u2-u4) du From here, elementary antiderivatives can be used: anti(u2) = (1/3)(u3) anti(u4) = (1/5)(u5) which yields a final indefinite integral in u of: (1/3)u3-(1/5)u5 + C where C is the constant of integration (since this is an indefinite integral). Back-substituting with the u-substitution from before (u=sin(x)), the final indefinite integral in x is: (1/3)sin3(x) - (1/5)sin5(x) + C

# What power does professor x have from x men?

Telepathy. He can read minds. He shoot strong mind-blasts. He has the most powerful mind of all the mutants in the world.

# How do you integrate x power x?

e^x/1-e^x

# What is the derivative of 1 divided by x to the third power?

1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.

# What is the Derivative of x to the power of x?

The solution to this is: (xx)'= (elnx to the power of x)'= (exlnx)'= (xlnx)'*exlnx= [x(1/x) + 1(lnx)]*exlnx = (lnx+1)*exlnx= (lnx+1)*xx

# X to the fifth power minus 32 divide by x minus 2 simplify?

x^5 - 32 = x^5 - 2x^4 + 2x^4 - 4x^3 + 4x^3 - 8x^2 +8x^2 - 16x +16x - 32 (second and third terms cancel, as do fourth and fifth etc) = (x - 2)*(x^4 + 2x^3 + 4x^…2 + 8x + 16) so (x^5 - 32)/(x - 2) = x^4 + 2x^3 + 4x^2 + 8x + 16

# What is x when x to the power of x equals 100?

Xx = 100 thus X = 3.5973

# X to the third power times x to the fourth power?

X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.

# Logx to the 2nd power equals 2 solve for x?

logx^2=2 2logx=2 logx=1 10^1=x x=10

# X to the 2nd power plus 5x plus 4?

(x + 4)(x + 1) x = -1 or -4

Updated Answer

In Algebra

# What is 6.78 x 10 to the 2nd power?

6.78 × 102 written in regular notation is 678

Answered

In Calculus

# What is x to the negative 2nd power?

X -2 same as saying 1/X2 ------

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In Algebra

# What is x to the 3rd power plus 3x to the 2nd power- 5x -4?

(x + 4)(x2 - x - 1)

Math and Arithmetic Supervisor

In Calculus

# 8.2 x 10 to the 2nd power divided by 6.3 x 10 to the 4th power?

8.2 x 102 ÷ 6.3 x 104 ≈ 1.302 x 10-2

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In Algebra

# What is x to the 2nd power plus x minus 56?

It is: (x+8)(x-7) when factored