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Beryllium is in the 2d period of the modern Periodic Table. Its electron config. is [He] 2s2 and forms the Be2+ ion by losing two elctrons and in this instance can be said to disobey the octet. In some compounds such as the hydride it also disobeys the octet rule. But in many others it does obey the octet rule! For example the difluoride, BeF2, is essentially covalent with four coordinate Be centers linked by flourine bridges.
Wiki User
∙ 9y ago
Wiki User
∙ 11y agoBe has 2 valence elelectrons. BeCl2 in the solid state does follow the octet rule, it has a chain structure with 4 coordinate tetrahedral beryllium atoms. There are "dative" bonds from Cl bringing the number of electrons around the Be to 8. The hybridusation is not sp3 as the bond angles are not tetrahedral.
In the vapour phase it forms a dimer, approxmate sp2 hybridisation wherether are 6 electrons around the Be.
At high temperature the dimer dissociates to monomeric BeCl2 which is linear. This has only 4 electrons around the Be.
Wiki User
∙ 16y agoIt needs an ionic bond, but I need to know why it needs and ioic bond??
Wiki User
∙ 13y agoThey don't have enough electrons
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How does oxygen not follow the octet rule?
It does follow the octet rule!
Does BeF2 obey the octet rule?
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
Does BeH2 violate the octet rule?
The octet rule only applies to elements that are heavy enough to have reached the second shell of electrons. In the first shell, the octet rule does not apply because the first shell is completed with only two electrons, not eight. So no, the octet rule does not apply to beryllium hydride.
Does AsH3 follow the octet rule?
PF5
Does BCl3 follow the octet rule?
nope
How does oxygen not follow the octet rule?
It does follow the octet rule!
What is octet rule and give two examples which do not follow this rule?
The octet rule is a rule in chemistry where elements want to form bonds to attain 8 electrons in their valence shell. An example of this would be sodium chloride. Bonds that don't have 8 electrons in their valence shell don't follow this rule
Does BeF2 obey the octet rule?
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
In which bonding patterns does X obey the octet rule?
no it does not follow octet rule
What rule do the nonmetal atoms follow?
octet rule
Does BeH2 violate the octet rule?
The octet rule only applies to elements that are heavy enough to have reached the second shell of electrons. In the first shell, the octet rule does not apply because the first shell is completed with only two electrons, not eight. So no, the octet rule does not apply to beryllium hydride.
Does BCl3 follow the octet rule?
nope
Does AsH3 follow the octet rule?
PF5
How many electrons must be gained to obey the octet rule for beryllium?
5 and your moms d
Does H2S follow the octet rule?
H2S does follow the octet rule. When you draw the Lewis Structure for H2S, it looks like this: If you count up the lone pairs and sigma bonds (each worth 2), there are 8, thus, H2S follows the octet rule.
How many valence electrons will beryllium gain or lose to fill its outer shell?
Beryllium will lose 2 electrons to satisfy the octet rule (to fill its outer shell).
Does AlCl3 follow octet rule?
no beacuse i dont know
