#include<stdio.h>
#include<conio.h>
int fib(int a);
main()
{
int a;
clrscr();
scanf("%d",&a);
for(int i=0;i<a;i++)
printf("%d\n",fib(i));
}
int fib(int a)
{
if(a==0)
return 0;
if(a==1)
return 1;
else
return (fib(a-1)+fib(a-2));
}
In algorithm:
1. Assign sum=0, A=0, B=1, i=1
2. Get the no. of terms upto which u want to generate the Fibonacci no, i.e., n.
3.Add A and B to get the next Fibonacci number
4. Assign the value of B to A i.e. A=B
5. Assign the value of sum to B i.e. B=sum
6. Write the value of su to get next Fibonacci number in the series.
7. increment i with 1 i.e. i=i+1 and repeat step 3,4,5,6 with the last value of i=n(n is the no. of terms which u wnt to generate Fibonacci no. series.)
8. Stop
Read more: Algorithm_to_write_a_Fibonacci_series
fibonacci heap is a heap
You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
Ronaldo! 'c' coding of Ricart-agarwala algorithm
Here is a good answer for recursion Fibonacci series. #include <stdio.h> #include <conio.h> long Fibonacci(long n); int main() { long r, n,i; printf("Enter the value of n: "); scanf("%ld",&n); for(i=0;i<=n;i++) { printf(" Fibonacci(%ld)= %ld\n", i,Fibonacci(i)); } getch(); return 0; } long Fibonacci(long n) { if(n==0 n==1) return n; else { return (Fibonacci(n-1)+Fibonacci(n-2)); } } for n=5; Output: Fibonacci(0)=0 Fibonacci(1)=1 Fibonacci(2)=1 Fibonacci(3)=2 Fibonacci(4)=3 Fibonacci(5)=5
yes we can do it,in c
fibonacci heap is a heap
what? Assuming you wanted an algorithm to find the nth number in the Fibonacci sequence: double Fib(int i) { double x = 1; double y = 1; if (i
Exactly what do you mean by 'C program in Java'
bisection algorithm (see link)Euclid's algorithm (see link)Fibonacci search (see link)
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
20 is not a term in the Fibonacci series.
#include<stdio.h> #include<conio.h> void main() { printf("The first 20numbers of Fibonacci series are:"); int a=0, b=1, c, n=2; printf("%d \t, %d", &a, &b); while(n<20) { c=a+b; printf("\t %d", &c); a=b; b=c; n++; } getch(); }
i dn't know. haha
This is not a homework board. I will give you a rough algorithm in C#int firstnum= 1;int finalnum = 1;int nextNumber;System.Console.Write(finalnum + " ");while (finalnum < 50){System.Console.Write(finalnum + " ");nextNumber = finalnum + firstnum;firstnum= finalnum ;finalnum = nextNumber;}
Fibonacci!
As you expand the Fibonacci series, each new value in proportion to the previous approaches the Golden Ratio.
Yes, this can be done. For example for Fibonacci series. You will find plenty of examples if you google for the types of series you need to be generated.