15x2 - 17x + 4 = 15x2 - 5x - 12x + 4
= 5x(3x - 1) - 4(3x - 1).
= (5x - 4)(3x - 1).
Thus the solution,
when 15x2 - 17x + 4 = (5x - 4)(3x - 1) = 0,
is: x = 4/5 or 1/3.
* * * * *
The technique, in case it is not familiar, is quite simple:
Step 1: Note that the three co-efficients of the given quadratic are 15, -17, and 4.
Step 2: We seek two numbers whose sum and product are -17 and 60.
(Note that 60 is, itself the product of 15 and 4.)
The two numbers we seek are -5 and -12.
Step 3: Replace the middle term, '-17x' with two terms, '-5x' and '-12x'.
Step 4: Continue factorisation easily, as shown. Then, combine like terms.
Step 5: To find solution, apply the following principle: The product of two factors is equal to zero if, and only if, one or other of the two factors is equal to zero.
3
104
4,5,6
89
pythagoras
Seventeen twelves = 204 So the answer is 204.5
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
X = √63
b= 10
b = 14324.80366
16
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal