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Gasoline must be measured by mass not volume.

So we have to convert from volume to mass and back to volume.

I left the units on so you could see conversion. \ denotes per and / denotes division.

Example:

5.2L/2=2.6L*2000rpm=5200L\m*.85=4420L\m*1.22g\L=5392.4g\m /14.7=

366.83g\m/760g\l=.48L\m

Explained:

1.)Only half of the engine fires per rotation for 4 stroke engine

Displacement/2= ans1 (Displacement in liters per 1 rotation)

2.)How much air will be moving through engine at RPM and 100% VE

ans1*rpm=ans2 (Amount of air moving through engine per minute 2 100% Eff.)

3.)Most Engine average 85% Volumetric Efficiency.

ans2*.85=ans3(More accurate amount of air moving through engine per min)

4.)Multiply the weight of dry air by the amount of air moving through the engine at a given rpm

ans3*1.22=ans4 (weight of the air in grams moving through the engine)

5.)Divide the amount of air by 14.7 (Stoich) for grams of gasoline.

ans4/14.7=ans5 (really rough estimate in grams per minute)

This is a rough estimate though. Gasoline engines don't work at exactly stoiche, they typically used to run richer because catolytic converters attempt to burn off unburnt hydrocarbons as they move through. So try 13 instead of 14.7.

6.)Find Liters by multiplying weight of fuel consumed by 750 or weight of 1L of gasoline

ans5/750=Liters per minute

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Q: How can you calculate fuel consumption as a function of rpm So for a given rpm and an engine size you can find the approximate fuel consumption liters per minute Does any one know of an equation?
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