Since a capacitor resists a change in voltage, it is used to provide voltage to the regulator circuit between the point in time where the rectifying diode turns off, and the point in time where it turns back on. It is a low-pass filter.
is it ? are you sure ? but i know so many circuit where capacitor is connected with ac supply . still , if u connected a capacitor to dc supply , then : 1. if it is in SERIES with the dc supply , it will block all the dc current as capacitor provides infinite resistance to dc current . application : where u want to block dc current.(simple high pass filter) 2. if it is in PARALLEL with the dc supply , it will not block dc current , but if any ac current comes out from the supply , the ac current will go through the capacitor , as capacitor provides small resistance to ac current. application : a) where u want to block ac current.(simple low pass filter) b) to filter the noise (ac components) of dc supply.
in a dc frequency=0 impedance is xc=1/2*pi*f*c so impedance infinite
It filters ac to pure dc
Yes.
Because it does not allow ac to pass through it...
when the DC current flows through the capacitor .the leakage of the charges is in capacitor called Dc leakage capacitor .
DC does not travel through a capacitor for long because there is a buildup of charge on the plates and when the voltage matches the supply voltage, mo more current flows. But capacitors are used to smooth a DC supply because a capacitor acts a bit like a small battery and can prevent any rapid fluctuations in the supply voltage.
At high frequency, capacitor can be considered as 1. Short Circuit in AC analysis. 2. Open Circuit in DC analysis. {because Xc= 1/(2*f*pi) where f= supply frequency,pi=3.14} As at high frequencies, in DC analysis, capacitor will be open circuited & can block the DC signal while AC signal is allowed to pass through.. Hence, this capacitor will act as a blocking capacitor for DC supply.
capacitor acts as a small battery ,during rectification ac to dc it gets some blank space (no current) to fill this current from capacitor is used.
Capacitor contains a dielectric sandwitched between two plates. So, it act as a charge storage device. When dc supply is given,it gets charged to its maximum capacity or potential equal to the supply, and then it act as a open circuit, since it has no way to discharge.
No, unless you have a pulsating DC
In case of dc there is no reactive components and current drawn from the supply is in phase with the voltage.due to absence of inductor and capacitor the reactive power demand in dc is zero.