If you're reading the numbers sequentially, keep a running total. Alternatively, pass all the numbers to a function using a variable-length argument. Alternatively push the numbers into a vector then sum the vector with the following function:
void sum_vector(std::vector<int> a)
{
int total=0;
for(int i=0; i<a.size(); ++i)
total+=a[i];
return(total);
}
sum = a + b + c;
int x = 1, y = 2, z = 3; int f = x + y + z;
Input a variable.
int* a = new int(40); int* b = new int(2); int x = *a + *b; // x = 42 delete b; delete a;
You can make use of pointers to achieve this.void add( int *a, int *b){(*a) += (*b);}Now if two numbers a and b are given and you need to store the value in variable c, then you would perform:c = a;add(&c,&b);
int main() { int a=10,b=20; while(a--) b++; printf("%d",b); } or: a -= -b;
In (a+bi) + (c+di), you add the real parts using the laws for real numbers and do the same for the imanginary parts. (a+c)+(b+d)i
R = (A > B && A > C) ? A : (B > C) ? B : C; // parentheses not necessary - for clarity only
It completely depends the datatype that you have assigned for the variables 'a' , 'b' , and 'c'. Check the compiler that you are using for the size of the datatype in bytes. Add them and thus you will get the answer.
You can also have any numbers like (a + c) and (b - c), where "c" is the irrational part, and "a" and "b" are rational.
Not possible. Of course you can call a function which does the addition for you, but function-calling is also an operator in C.
To use C++ in Netbeans you will need a C++ compiler.