It really depends on what units you use to measure time: seconds, minutes, or hours! It also depends on the value of current flowing, which you don't specify. So your question cannot be answered.
A series circuit has 100mA flowing through a 1.5kohm load. The power dissipated by the load is equivalent to 15 Watt. This is based on the formula, power is equals to square current times load.
divide 0.108 gm by 1 coulomb of charge because e.c.e equals mass in gm/charge
Potential difference equals current multiplied by resistance or E = IR therefore the answer to your question is 25 volts
The voltage drop is equal to the total resistance across which it is dropped multiplied by the current flowing through this resistance. i.e. V=IR (where V is the voltage drop, I is the current and R is the resistance) Thus, I=V/R So I=5/1000 A = 5*10-3 A = 5 mA So the current flowing through your circuit is 5mA. Note that this answer is theoretical, and that it may differ from what you observe in practice due to component tolerances (resistors with the gold band at the end are only accurate to within 10%).
No.there can be electric field on the Gaussian surface even if the charge enclosed by it is zero.However ,net flux will be zero through the surface.
the point would be the kolwea-4 where the positive charge is q3. xoxoxo
eight eight
No.
using the t-table determine 3 solutions to this equation: y equals 2x
The Ionic charge of H2O is 0 because H has a +1 charge and there are two H so it equals +2 and O has a -2 charge. So they balance out to a charge of zero
determine whether each relation is a function y equals -8
zero .. such an atom is neutral. No net charge