0
MDCCXIIC.
Breakdown:
M(1000)+D(500)+C(100)+C+[C-{X(10)+I(1)+I}]
1700+{100-12}
1700+88
1788
Improved Answer:-
In today's notation of Roman numerals 1788 = MDCCLXXXVIII
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∙ 12y ago
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What is the Roman numerals for 1788?
MDCCLXXXVIII
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