'Poor power factor' means that a load is drawing more load current is necessary for the amount of energy it consumes. The result is larger voltage drops along the supply lines and greater energy losses along those same lines. To overcome these problems, it would be necessary to install cables and other equipment with larger cross-sectional areas -this is expensive, so it's much easier and cheaper to improve the load's power factor. To encourage consumers to do so, utility companies include a surcharge if the power factor falls below a certain value. All of this only applies to industrial/commercial loads, it does NOT apply to residential loads.
Poor power factor has the following effects on the power supply:
A three-phase 'unbalanced' system refers to the load, as the supply voltages are unaffected by load. So the phase-angle and, therefore, the power factor of each phase will be different -i.e. there will be three different power factors.
Two factors reduce the power used by a piece of equipment compared to the volt-amps drawn from the supply: power factor and harmonic factor. Both factors increase the power transmission losses incurred in supplying a given amount of power.The power factor is less than 1 when voltage and current are out of phase with each other.When they are in phase the power equals the volt-amps except for a nonlinear load with a current that is not proportional to voltage. This generates harmonics in the current and the effect is that the power is less than the volt-amps, by an amount equal to the harmonic factor.
No. Your energy meter monitors the supply voltage and the in-phase component of the load current, so improving your power factor will have no effect on your energy consumption and, therefore, your electricity bill.
It depends on how the capacitor is connected and whether the supply voltage is a.c. or d.c. Assuming you are talking about a power-factor improvement capacitor (connected in parallel with an inductive load, supplied with a.c.), then the supply current will reduce.
It depends on how the capacitor is connected and whether the supply voltage is a.c. or d.c. Assuming you are talking about a power-factor improvement capacitor (connected in parallel with an inductive load, supplied with a.c.), then the supply current will reduce.
The mother board, power supply, and chassis
Efficiency is defined as the ratio between the output power and the input power of a machine, expressed as a per unit or percentage. Power factor improvement has absolutely no effect on the behaviour of a load. All it does is to reduce the magnitude of the load current. A reduction in load current means that less copper can be used in the supply of energy to the load. However, it doesn't effect either the output or input power of the load. So the answer is no, power factor has no effect on the efficiency of a load. You could argue, however, that if improving the power factor of a load reduces the supply current, leading to lower line losses, then there is an improvement in the efficiency of the supply system.
For a residential consumer, power-factor improvement has absolutely no effect on one's electricity bill. Adding power-factor improvement capacitors at the point of supply will have absolutely no effect upon the operation of the load circuits, but it may act to reduce the supply current. But reducing the supply current will not reduce one's energy consumption.
Power factor is a measure of the ratio between the "True Power" and the "Apparent Power" of a system. THe variation from unity arises from the effect of certain components (namely capacitors and inductors) on an AC waveform, causing a phase shift between the current and the voltage. As a DC supply does not suffer from these reactive losses there is no reactive power and the current and voltage are always "in phase". With a phase angle of 0 degrees, the power factor is the cosine of the angle... cos 0 = 1 therefore unity power factor!
For a single-phase system, active (or 'true') power is the product of the supply voltage, the load current, and the power factor of the load.
no.... the power factor of any machine should be as near as to 1 when the power factor becomes near to 1 there is no need to the alternator to supply the reactive power.. but in general all most all the loads in the power system inductive in nature the power factor is becoming lagging(<1) so to avoid this the power generating companies and the govt. are recommending the people to have the capacitors at the load ends....... since the capacitive reactance can nullify the effect of the inductive reactance this will try to improve the power factor
A three-phase 'unbalanced' system refers to the load, as the supply voltages are unaffected by load. So the phase-angle and, therefore, the power factor of each phase will be different -i.e. there will be three different power factors.
power factor meters are connected across the supply
No, but power factor may affect the choice of a conductor's thickness! The whole point of power-factor correction is to reduce the load current in order to enable conductors of lower cross-sectional area to supply a given load.
ATX is the form factor.
As power factor is the cosine of the load's phase angle (the angle by which the load current lags or leads the supply voltage), it is impossible for power factor to exceed unity (1), so your question doesn't really make any sense.
it will improve the power factor... The angle between voltage and current will decrease depends on capacitor value.