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How does the centripetal force with the speed of rotation of the body with constant mass and radius of rotation?
Wiki User
∙ 7y ago
You can calculate the centripetal ACCELERATION with one of these formulae:
acceleration = velocity squared / radius
acceleration = omega squared x radius
Acceleration refers to the magnitude of the acceleration; the direction is towards the center.
Omega is the angular speed, in radians per second.
To get the centripetal FORCE, you can use Newton's Second Law. In other words, just multiply the acceleration by the mass.
Wiki User
∙ 7y ago
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If the radius of rotation and the mass being kept constant how does the centripetal force vary with the speed of rotation of the body?
Recall centripetal force = m v^2 / rAs m and r are found to be constants then centripetal force F is directly proportional to the square of the velocity of the body
Can centripetal force produce rotation?
no, but rotation can produce centripetal force
If the magnitude of applied force falls short of required centripetal force then the object will move away from the centre of the circle?
Yes. It would spiral away such that the radius of rotation will increase, until the radius is large enough for the centripetal force to decrease to the applied force. (Centripetal force= mv2/r)
How is the radius of rotation related to the centripetal force and angular velocity?
Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius
Centripetal force can it produce rotation?
A centripetal force is, by definition, a force that makes a body follow a curved path. So, yes, a centripetal force causes rotation about a point in space.
When does centripetal force double?
Since a=Rω², when you double the radius, but hold the angular velocity constant, you double the force. Also when you increase the angular velocity or velocity by a factor of √2 and hold the radius constant.
What is the measure of how effectively a force causes rotation?
centripetal force
How do you solve for revolutions per second give centripetal force and radius?
One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.One formula is: centripetal force = speed2 / radius. Solve it for speed, then convert that to revolutions per second.
What is the relationship between centripetal force and velocity?
Centripetal force is = mass * velocity square divided by radius
How is the centripetal force affected by the mass and the radius?
Centripetal force as well as centrifugal force is given by the expression F = m v2 / r Hence F is directly proportional to the mass of the body but inversely related to the radius of the curvature So higher the mass more centripetal force in needed Lesser the radius, more centripetal force is required.
How do they affect the centripetal force?
If an object moves in a circle, the centripetal acceleration can be calculated as speed squared divided by the radius. The centripetal force, of course, is calculated with Newton's Second Law: force = mass x acceleration. Therefore, the centripetal force will be equal to mass x speed2 / radius.
What factors affect the increase of the centripetal force on a particle in uniform circular motion?
The centripetal force on a particle in uniform circular motion increases with an increase in the mass of the particle or the speed at which it is moving. It also increases if the radius of the circle decreases, as the force required to keep the particle in the circular path becomes greater when the circle is smaller.
