We have to assume that the bottom slopes evenly ... flat with a steady-slope from
one end to the other, with no breaks or "landings". Then we can use the average
depth of 4-ft for the whole pool.
Volume = (16' x 32' x 4') = 2,048 cubic feet = 15,320 gallons (rounded)
16 gallons is 2,048 ounces @128 fluid ounces per gallon.
If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.
One, if the pool is shallow enough!
24,685.79 gallons
It really depends on the depth of the shallow end. However, let's say the shallow end is three feet deep. In that case, the pool holds up to about 22,980 gallons of water.
10000000 gallons of water ;) it's true, my teacher told me
If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 21,722 gallons of water.
18,691.2 gallons if shallow end 4'
25000 gallons
20000
Length x width x average depth*. Multiply result by 7.48 to determine volume in gallons.* 'average depth' is shallow end + deep end divided by two
You need more information. But, let's assume the pool is 8 feet deep at the deep end and 3 feet at the shallow end. If the pool is rectangular, the total volume will be 28,798 gallons of water.