Hi I have an indirect method: My car has aprox 60kW power. I know the max. power of the engine allows for no acceleration at 150km/h. This, all the power extracted from the oil goes to drag (air, and some road, and internal efficiency of car engine, transmission) This means, in 1 hour I will consume 60kWh having travelled 150km. The fuel efficiency of my car is 14km/l at that speed. That means, about 11 liters for the 150km (60kWh) So, at the efficiency of my car, 11 liters are giving an output of 60 kWh. or 1 liter 5.5 kWh So, for car fuel (not diesel though), 1 m3 1000 liters = 5500 kWh. I know efficiency of a car engine is about 30%, so the burned kWh will be about 16000 kWh. Bye Alejandro ====== This question involves dissimilar units, so cannot be answered without more information. 1 kWh = 1 kilowatt hour. A Wh is a Watt-hour. If using an appliance that consumes 1W, after 1 hour it will have consumed 1Wh of electricity. 1 kWh = 1,000 Watt-hours. So, running your 1W appliance will consume 1kWh after 1,000 hours, or running a 1,000W appliance will consume 1kWh after 1 hour. A 60W light bulb would take 16-2/3 hours to consume 1 kWh. m3 typically refers to a cubic meter, also abbreviated cu. m. and CBM (in the freight industry). To convert the stored chemical energy in oil into electricity requires a conversion of energy. For example, the oil could be refined into flammable products, such as gasoline, to fuel an internal combustion engine driving a generator. This question does not specify a type of oil. However, if using something like light, sweet crude, by volume only about one third of the oil can be converted to gasoline. The remainder can become other petroleum products, such as diesel fuel. Alternately, with the proper wick and fuel-to-air ratio, the oil could be burned, and the resulting heat used to heat water to power a steam turbine, again producing electricity. So, the amount of kWh which can be obtained from a cubic meter of oil depends on the type of oil (unspecified), how thoroughly it can be burned (unspecified), and how efficiently the energy released from burning can be converted into electricity (unspecified).
0.001167 kWh/°C/l at 100% efficiency.
The result will be 1 m3 of CO2 and 2 m3 of H2O gas (and 2 m3 of O2 will be consumed).This is determined by the stoichiometry of the balanced reaction:CH4 + 2O2 ---> CO2 + 2H2O
The electric meter uses kWh (kilowatt x hours) as units; a Joule is a watt x second. Therefore, a kWh has 3.6 million joules. Just multiply by this number.
The 2008 BMW M3 runs on premium unleaded (required).
The density of pure water is 1000 kg/m3. The SI unit is really kilograms per cubic meter. ------- The density of ultrapure water at 4 0C is 999,9720 kg/m3.
The density of oil is 820 kg/m3.
Over 640,000 on the average
There are 6.289811 barrels (petroluem) in 1 m3.
one cubic feet = 1028 Btu
It would be about 5.88 barrels. 10,000 kWh / 1,700kWh per boe = 5.882352941176471.... Source: http://bioenergy.ornl.gov/papers/misc/energy_conv.html Formula: Barrel of oil equivalent (boe) = approx. 6.1 GJ (5.8 million Btu), equivalent to 1,700 kWh.
1 mwh = 1000 kwh hence 4 mwh = 4000 kwh
Your question is not very specific, as 'oil' is a very broad term. Crude oil is never burned straight, it is always processed. I will assume gasoline is what is being used. Gasoline produces 36.6 kWh of power per one US gallon. Therefore: (36.6 kWh/ 1 gal) = ( 1 kWh/ X gal) (1 * 1) / 36.6 = X X ~= 0.0273 gallons So it takes about 0.0273 gallons of gasoline to produce one kWh of power. Some digging on various sites tells me that about 55% of crude oil (per gallon) gets processed into gasoline. So we take our number of gallons and multiply it by 155%: 0.0273 gal/gas * 1.55 ~= 0.0423 gal/oil So it takes 0.0423 gallons of oil to generate one kWh of power.
it is 991 kg/m3
969 (kg/m3)
One gallon of #2 fuel oil gives approximately 41 kWh
1000000
about 10,000 KWh