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2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H)

= 9.21 X 1022 atoms of Aspartame

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9y ago
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12y ago

9.214 x 10^18 molecules

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Q: How many molecules of aspartame are present in 4.50 of aspartame?
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