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A calcium atom will transfer its two valence electrons to two separate iodine atoms in the formation of calcium iodide. The calcium atom becomes a Ca2+ ion, and each iodine atom becomes a 1- iodide ion. The electrostatic force of attraction between the oppositely charged ions forms ionic bonds between the ions.

Ca + I2 --> Ca + I + I --> Ca2+ + I- + I- --> CaI2

Overall reaction:

Ca + I2 ---> CaI2

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Q: How many valance electrons are transferred from the calcium atom to iodine in the formation of calcium iodide?
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