Fully loaded - 2.62 amps at 11kV. The no load depends on the transformer design, but it will usually be significantly less than the full load amps (not sure on this size, but on larger Transformers it is typically ~.05 - .1% full load, so you'd be looking at ~2.5 mA RMS).
The connection type is not important. Transformers are very efficient, thus there is not a whole lot of loss in the "average" transformer. The actual loss will depend on the design criteria of the transformer.
2.6A at full load. The no load per phase draw, or the no load losses, will be very small; perhaps 1% of full load for a "bad" transformer.
Transformers are very efficient. There are two losses you must be concerned with - the no load losses, or magnetizing losses, which will be very small, and the Copper/I^2*R losses, which change depending on loading.
A quick Google search brings up an 11kV 50kVA transformer with no load losses of 250w and full load losses of ~1kW. When energized, this transformer will use 250 watts all the time, and depending on loading will use up to 1kW.
no becouse transformer function depends on no of coil in primary and secondry coil
When the generator is loaded, flux per pole is reduced due to armature reaction.
Ostrich
In the visible spectrum or the infrared? Either way, if your earth wire is glowing you have a problem. Your earth wire is not intended as a current carrying wire. If the wire is loaded to the point that it glows then your circuit/breaker is not wired correctly and the earth wire is being used as an unintended path and is a hazard. Earth wires are not sized properly to carry current.
For an analog ohmmeter, with a needle that moves left and right: The needle is spring loaded; when current is running through the meter, the current causes a small magnetic field in the windings of the meter mechanism, causing it do deflect to the right. If you're measuring current or voltage, if no current is running through the meter, then no deflection, so it should read zero on the left hand side of the scale. When measuring ohms (resistance) on an unenergized circuit, the battery in the meter provides the current. When you short the 2 leads together you have zero resistance to current (0 ohms). When you have an open circuit, no current flows, so there is an infinite resistance. So infinity is on the left side of the scale when no deflection, and zero is on the right side with maximum deflection (maximum current).
when your current transformer is over loaded make sure it turns back into a car and drives away
When working on a current transformer the secondary windings must be shorted. <<>> Properly loaded
The primary current on a loaded transformer depends on the secondary current, which is determined by the load. So, if you know the secondary load current, then you can use the turns ratio of the transformer to determine the primary current:Ip/Is = Ns/Np
The terms, 'primary' and 'secondary', describe how a transformer is connected and his nothing to do with which is the lower- and higher-voltage winding.The primary winding is the winding connected to the supply, while the secondary winding is the winding connected to the load. So, for astep-up transformer, the secondary winding is the higher voltage winding, whereas for a step-down transformer, the secondary winding is the lower voltage winding.For a loaded transformer, i.e. a transformer whose secondary is supplying a load, the higher-voltage winding carries the smaller current, while the lower-voltage winding carries the higher current.
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
no becouse transformer function depends on no of coil in primary and secondry coil
A transformer's 'no load' current is not 'high'. On the contrary, it is zero!'No load' means that there is nothing connected to the secondary (output) of the transformer -i.e. it is an open circuit. So a transformer's secondary 'no load' current is zero! The primary current still has to provide a magnetising current, but that current will be very small.Don't forget, a 'light load' means little current is drawn, so the load must have a high resistance; a 'heavy load' means lots of current is drawn, so the load must have a low resistance.
The lower the impedance, the lower the voltage drop across the transformer as it is loaded. This means regulation is better, since voltage variance is smaller.
Unless the transformer is an isolation transformer, whose primary and secondary voltages are the same, the cross-sectional area of the primary and secondary winding conductors are normally different. The higher-voltage winding has a smaller current flowing through it than the lower-voltage winding when the transformer is loaded. So the higher-voltage winding is manufactured using a conductor with a smaller cross-sectional area, therefore a smaller diameter.
i understand that YNaOd1 represent an auto transformer with HV winding as wye connected and loaded tertiary. Please correct me if i am wrong.
The lower the impedance, the lower the voltage drop across the transformer as it is loaded. This means regulation is better, since voltage variance is smaller.
A transformer is often represented by an equivalent circuit, in which the transformer itself is considered to be 'ideal', and its basic losses are then represented as resistance and reactance in series with both the primary and secondary windings for a loaded transformer, or just on the primary side for a transformer on open circuit.The transformer's primary flux comprises two components: the main flux, which links the primary and secondary windings, and a leakage flux which links just the primary winding. The leakage flux is considered arising from a self inductance in series with an 'ideal' primary winding. The reactance of this inductance is termed the primary leakage reactance. The voltage drop across this reactance will lead the primary no-load current by 90 degrees which, when added to the voltage drop across the resistance of the primary winding, acts to reduce the back emf of the primary winding below the value of the applied voltage and cause it to lag.A similar explanation accounts for the an inductance and resistance in series with the secondary winding, when the transformer is loaded.