Kinetic energy = 1/2 M V2
At the lower speed, the car's KE is (500) (1)2 = 500 joules
At the higher speed, the car's KE is (500) (2)2 = 2,000 joules
The difference is the energy i.e. the work you have to put into it
to raise the speed from 1 m/s to 2 m/s.
(2,000 - 500) = 1,500 joules
30 J
375 Js (((((((((((: this is the right answer
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
Her average speed was 10 m/s. You probably missed something in the question, there isn't enough there to determine "how much it increased by".
10kg
1500 j
537.5 J
work=mass*speed,5*2=10
1,500 J
3000j
312.5 J
30 J
3000 J *Shelby Sarah*
750 j
375 Js (((((((((((: this is the right answer
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.