A linear series with "i" terms can be summed by finding the average of the first and last terms, then multiplying by the amount of terms.This sequence can be written as follows:
ai= 11 + 1(i-1)
= 11 + i - 1
= 10 + i
11 is the first term, 1 is the difference between terms which gets multiplied by (i-1)
So the fourth term a4= 10 + 4 = 14
Sum total = i * (a1+ ai)/2 (no. of terms * average of first and last term)
= 10 * (11 + 20)/2
= 10 * (31/2)
= 155
12.
the answer is 12.
23
12
The sum of 3/4 and 1/6 is 11/12
11 and 1
11 and 12.
66.
It is: 11/12 times 24 = 22
The factors are 1 & 11 !
-11 and -1
The sum of 11/12 and 2/3 = 1 7/12