as power=P=W/t=Fd/t=(10)(10)/10=10Watt
Work in Joules = force x displacement
= 100N x 10meters
= 1000 Joules
Power in Watts = work/seconds
= 1000 Joules / 5 seconds
= 200 Watts
200 W
Power is the rate at which energy is being used. It is expressed as P = W/t, work divided by the time in which it is performed.
Example : where work is expressed in joules (kg-m2/sec2) and power in watts (joules per second or kg-m2/sec3)
The work is 200 Newtons x 10 meters or 2000 joules. As this work is to be done over 8 seconds, the power is 2000/8 or 250 watts. This is the power required to complete the work in 8 seconds.
Work is force times distance. Power is work per unit time. Looks like you have all you need.
Work= 500 Joule.
Power= 33.333 Watt.
The idea is to multiply force x distance. (This assumes the force acts in the same direction as the movement. Otherwise, the work will be less.)
10 x 5 = 50 newton-meters = 50 joules
Work done=0.5*5=2.5J
10w
A wheel requires a smaller amount of force to be moved than an axle. Combined, a minimal amount of force is used to move the wheel and in turn is transferred from the wheel to the attached axle, to move the axle. Alone the axle would require a greater amount of force for it to be turned.
Yes, it is possible for a smaller force to have a large torque because it is usually located at a much greater distance from the center of rotation. Torque is calculated by multiplying the distance by the force.
A force will not increase or decrease an acceleration. If the force is constant, it will cause a constant acceleration. It may increase or decrease the speed. The change of velocity - for the same force - is the same, whether the speed is increasing, decreasing, or just changing direction.
The technical definition of 'work' in Physics is (force) times (distance).So I suspect the factors you're fishing for are force and distance.
it measures how much force is needed to to move it
Over 200 pounds of pressure.
USB 3.1 (C) can deliver a power output of up to 100 watts (20 volts and 5 amps).
5
1/4 the output force.
That would depend on the power output (watts) of the circuit. Volts times the Amperage equals the Wattage of the circuit. You do not have enough information in your question. Volts is the force applied to move the electrons in the circuit, and amps are a measure of the quantity of electrons moved through the circuit over time. Thus a circuit of 415 volts and 1 ampere will deliver 415 watt-hours of power. Yet a circuit of 1 volt at 415 amps will deliver the same 415 watt-hours of power, but with less force.
This equation will tell you how much force is exerted by a bullet, for example, on a target.
It's how much power the tractor can continuously deliver to an auxiliary piece of equipment.
A factory stock Kawasaki Brute Force 750 has 52 horse power.
The Pyle is a lower end lower powered model that will only push around 70 watts of power.
yes
force in horse power for rocket at the time of launching
10