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Maximum memory addressing capacity of 8086?
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since 8086 has 20-bit address line therefore 2^20=1048576 bytes=1048 KB=1MB Hence Addressing up to 1MB memory vivek Lunkar
Assuming your memory card slot(s) permit, 2 to the power of 32 = 4294967296 which is apprx 4 GB
What is the maximum memory capacity that can be connected to a microprocessor data bus with 16 lines and the address bus has 20 lines?
You can address 2^20 (or 1,048,576) locations. Each location will consist of 16 bits (1 or 0) which is commonly called a Word (though that isn't always the case). I think wha…t you're really looking for is the answer in bytes. Each data bus line holds a bit, 8 bits is a byte, so you're data line is 2 bytes. Since each location holds two bytes, this would be 2,097,152 bytes, or 2MB
Not possible to answer the question. You need to provide more details. To be precise, the maximum addressable memory is limited by the memory controller, not the CPU, and c…an be further limited by the operating system.
2 ki power 64 memory addressing capacity hogi
32-bit system can address: 2 to the power of 32 = 4.3 Giga different addresses, corresponding to 4.3 GB of RAM as it needs to manage other stuff than the RAM (motherboard,… expansion cards, including the graphics card), it remains only about 2.8 to 3.3 GB of RAM addressable following configuration PC.
for a 32-bit processor with 8-bit opcode: 2^(32-8) bits == 2^24 bits = about 16.8 MB
The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 2 20 or 1,048,576.
It depends on the processor and the operating system. . In the 8086/8088, with a 20 bit address bus, you can address 1,048,576 bytes of memory. . In the 8085, with a 16 bi…t address bus, you can address 65,536 bytes of memory. . In the IA-32 architecture (80386 and higher in 32 bit mode), you can address 4,294,967,296 bytes of memory (physical) minus about 805,306,368 bytes of memory for overhead (operating system). . In the IA-64 architecture (80686 running in 64 bit mode on 64 bit Windows) you can address 206,158,430,208 bytes of memory.
2^16. That is, 1MB. Similar way, 32-bit can address 2^32 which is 4294967296 bytes of memory, which is 4GB.
You cannot address 1GB memory with the 8085 or the 8086/8088 without some kind of external demultiplexor that is software controlled. The address bus on the 8085 is 16 bits, g…iving addressibility of 64KB; while the address bus on the 8086/8088 is 20 bits, giving addressibility of 1MB. To address 1GB, you need a 30 bit address bus.
The 8086/8088 has 20 address lines. It can access 2 20 , or 1MB, or 1,048,576 bytes of memory.
It can only go to a capacity of 64GB trust me
That actually depends on your motherboard and your operating system. For instance, Windows XP on a 32 bit system can use a maximum of 4 gigabytes if the motherboard supports i…t. 64 Bit Windows 7 can operate with a max of 8 gb for Home Basic or up to 192 Gb for Ultimate. The amount of ram for older systems is far less than the max for XP.