first: -20 dB/decade
second: -40 dB/decade
1/6 on the first roll, and 1/6 of rolling a six on the second roll. Overall, the chances of you rolling a 5 on the first and a six on the second is 1/3.
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
Ideal filters having sharp cut-off & sharp cut-in for LPF & HPF but in practical filters there is some roll-off rate based on the order.
1/6 + 1/6 = 1/3
It is 1/12.
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
1/6*1/2 = 1/12
and the question is ... ?
2/12 or 1/6
No. If you have a good combination after the first or second roll you can score it right there.
No. Each roll is independent of the previous roll (on a fair dice). The same is true for flipping a coin. Getting a six your first roll does not make you any more or less likely to roll a six the second time.
Assuming that a dice roll is purely random, there is a 1 in 6 probability of landing on any number. Since the second roll depends on the probability of the first, they factor together: First Roll: 1/6 Second Roll: (1/6)(1/6) = 1/36 If you were rolling both dice at once, however, the math would be completely different.