For a series circuit, the applied voltage equals the sum of the voltage drops
In a series circuit the total voltage is the sum of the voltage drops across all the component in series. When the voltage drops across each the individual components are added up, they will equal the supply (or applied) voltage.
Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".
When a current flow on a conductor , or load or resistor, some voltage will drop across that load or resistor.AnswerA voltage drop is the potential difference appearing across individual components in a circuit, necessary to drive current through those components. The sum of the individual voltage drops around a series circuit will equal the supply voltage applied to that circuit.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
The applied voltage is 53+28 = 81V.
In a series circuit the total voltage is the sum of the voltage drops across all the component in series. When the voltage drops across each the individual components are added up, they will equal the supply (or applied) voltage.
The two basic circuit types are series circuits and parallel circuits. In a series circuit, all the current flows through each component, and each one drops some of the applied voltage. In a parallel circuit, the applied voltage is dropped across each parallel component and current "splits" so some flows through each component.
Yes
The voltage applied and the resistance across it.
Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".
When a current flow on a conductor , or load or resistor, some voltage will drop across that load or resistor.AnswerA voltage drop is the potential difference appearing across individual components in a circuit, necessary to drive current through those components. The sum of the individual voltage drops around a series circuit will equal the supply voltage applied to that circuit.
this is the amount of voltage a circuit can hold.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
The applied voltage is 53+28 = 81V.
By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.
No. But bear in mind that, in the case of a.c. circuits, 'total', means the phasor (vectorial) sum of the voltage drops, NOT the algebraic sum.
The voltage is greater than the applied voltage, why?