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If 'f' is the focal length of the lens, and 'o' is the distance between the lens and the object, then the distance between the lens and the image is: ('f' times 'o') divided by ('o' minus 'f')

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Q: The distance between the lens and the image?
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Related questions

How can you tell what the focal length is for a lens?

Easy way: Use it to form an image of the sun or moon, and measure the distance of the image behind the lens. When the object is at infinity, the distance between the lens and the image is the focal length of the lens.


Which lens always forms a diminished image?

concave lens formed virtual,erect and diminished image irrespective to the distance between the object and lens.


How does the thickness of a lens affect image distance?

If the lens are thicker it affects the image distance.


Does the thickness of a lens affect the image?

If the lens are thicker it affects the image distance.


The image produced by a convex lens depends on what?

The image depends on the distance the object is from the lens.


What is the minimum distance between an object and its real image formed by a convex lens?

Find the smallest distance between the object and a real image, when the focal distance of the lens is2. Relevant equations, whereis the distance of the object from the lens andis the distance of the image.3. The attempt at a solutionI'm not even sure, what I'm trying to do here, since the definition of a real and virtual image is a bit vague to me. But I've got something...Letbe the desired distance. From the equation above we getso. Thenor. We get the same for, so the distance would be


How does the distance between an object and a convex lens affect the image formed?

It should appear the same.


What two factors determine the type of image formed by lens?

The focal length of the lens and the distance between the lens and the object.


Which lens always produces an image that is upright?

Concave lens (diverging) produces an upright image that is virtual. Although to create a real upright image would require 2 convex (converging) lens with a distance of their respective focal lengths between them.


How to calculate x of a lens knowing only the focal length which is the distance from the lens to the image of sun formed by it correct me if I'm wrong?

1/(focal length) = 1/(distance of object) + 1/(distance of image) is the formula for calculating x of a lens knowing only the focal length which is the distance from the lens to the image of sun formed by it.


What is a negative lens is the same as?

If the lens equation yields a negative image distance, then the image is a virtual image on the same side of the lens as the object. If it yields a negative focal length, then the lens is a diverging lens rather than the converging lens in the illustration.


How do you find how far an image is formed from the lens if you have the distance from the lens to the object and the focal length how do you solve for distance from image that is formed?

Here's the equation you want. It's called the "Lensmaker's Formula".1/i + 1/o = 1/fi = image distance from the lenso = object distance from the lensf = focal length of the lens