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The oxidation number of chlorine in the compound PbCl2 has to be?
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∙ 14y ago
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∙ 14y ago
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What is the oxidation number of chlorine in pbcl2?
The chlorine in PbCl2 exists as chloride ions, and the oxidation number of chloride ions is always -1.
Elements with an oxidation number of 1 include what?
The oxidation number of lead (Pb) in the compound PbCl2 has to be what?
The oxidation number of lead Pb in the compound PbCl2 has to be?
+2
The oxidation number of cholrine in the compound PbCI has to be?
-1. However PbCl is not a compound of lead- PbCl2 and PbCl4 are
How many atoms of chlorine are there in 445g of lead 2 chloride?
To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.
What is the oxidation number of chlorine in the compound pbCl2 has to be?
-1
What is the oxidation number of chlorine in pbcl2?
The chlorine in PbCl2 exists as chloride ions, and the oxidation number of chloride ions is always -1.
Elements with an oxidation number of 1 include what?
The oxidation number of lead (Pb) in the compound PbCl2 has to be what?
The oxidation number of lead Pb in the compound PbCl2 has to be?
+2
Elements with an oxidation number of 1 include what elements?
The oxidation number of lead (Pb) in the compound PbCl2 has to be what?
The oxidation number of cholrine in the compound PbCI has to be?
-1. However PbCl is not a compound of lead- PbCl2 and PbCl4 are
NAME THE ELEMENTS PRESENT IN THE FOLLOWING COMPOUND PbCl2?
Lead and Chlorine
How many atoms of chlorine are there in 445g of lead 2 chloride?
To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.
Name the elements in compound PbCl2?
Pb = lead Cl = chlorineThis compound has 1 lead atom and 2 chlorine atoms.
Is PbCl2 a molecular compound?
yes
Why Pbcl2 is ionic and Pbcl4 is covalent?
apply fazan's rule, greater the charge on cation more is the polarising power and hence more covalent character polarising power of pb4+>pb2+ thus pbcl4 is more covalent than pbcl2 conversely pbcl2 more ionic than pbcl4
What is the reaction between nacl plus pbno3?
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
