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That has no effect on the resistance. The current doubles also.

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Q: What happens to a parallel circuit resistance if the voltage applied is doubled?
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If the resistance in a circuit is doubled while the voltage remains the constant the current is?

It is halved. coz voltage=current * resistance


What happen to current in a circuit if the voltage is not charge but the resistance is doubled?

The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.


What is the effect on current in a wire if both the voltage across it and its resistance are doubled?

it will cause a Short Circuit


What happens to circuit if its resistance is doubled?

as per ohm law current is directly proportional to the applied voltage and inversely proportional to the resistance now u can calculat according to the formula by by putting the considered value and then by changing the values according to the question u will get the result to Analise the difference.


What happen to current in a circuit if the voltage in not charged but the resistant is double?

In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.


What happens to the current of the wire when the length increases?

resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.


If you doubled the load resistor in a wheatstone bridge. the load current would not be half as much Why not?

Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.


What are four characteristics of parallel circuit?

an example would be thus. if you had say 2 1.5 volt batteries each say .006 amps. When these batteries are in series the positive end of one is in contact with negative end of the other, pretty much like a common flashlight, and the voltage would be 3 volts., .006 amps. When the same two batteries are connected negative to negative and positive to positive the voltage would still be 1.5 volts but the amperage would be .012 amps. (amps doubled when in parallel, voltage doubled when in series)


A wire replaced with the same type and size but twice as long as the original the resistance is what?

The resistance is doubled.


Voltage across resistor is doubled the current is?

Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.


When the voltage in a series circuit is doubled while the resistance remains the same the power increases by?

If the voltage doubles while the resistance remains the same, the power increases by a factor of four.Power = voltage times currentCurrent = voltage divided by resistanceSo, power = voltage squared divided by resistanceThis has nothing to do with being in a series circuit. It is simply Ohm's Law and Joule's Laws.


What happens to the current in a circuit if one resistance is doubled or halved?

P1 = V I1, Therefore, if P2=0.5*P1, thenI2=0.5*P1/V, or 0.5*I1and if P3=2*P1, thenI3=2*P1/V, or 2*I1In other words, current is proportional to power and inversely proportional to voltage.