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I = E/R

If resistance is constant, then current is directly proportional to voltage.

Double the voltage ===> the current will also double.

Q: What happens to the current when the voltage is doubled and the resistance is constant?

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That has no effect on the resistance. The current doubles also.

The current is doubled.I = V/RI=2V/RLets assign arbitrary numbers to voltage and resistance to evaluate what happens. Voltage will be 8 volts and resistance will be 2 ohms.I = 8/2 Therefore current = 4ampsIf voltage is doubled then,I =2(8)/2I=16/2I = 8 amps

Impedance of a coil or a capacitor does depend on the excitation frequency,but resistance has no relationship to frequency.

The current will take the path of least resistance.

resistance increases

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It is halved. coz voltage=current * resistance

That has no effect on the resistance. The current doubles also.

resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.

Since resistance is the ratio of voltage to current, we can say that halving the resistance will result in twice the current.

The current is doubled.I = V/RI=2V/RLets assign arbitrary numbers to voltage and resistance to evaluate what happens. Voltage will be 8 volts and resistance will be 2 ohms.I = 8/2 Therefore current = 4ampsIf voltage is doubled then,I =2(8)/2I=16/2I = 8 amps

Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.

P1 = V I1, Therefore, if P2=0.5*P1, thenI2=0.5*P1/V, or 0.5*I1and if P3=2*P1, thenI3=2*P1/V, or 2*I1In other words, current is proportional to power and inversely proportional to voltage.

If the load resistance is constant, then increasing the voltage will increase the current by the same proportion -i.e. doubling the voltage will double the current.

the current doubles.. explanation:V=IR hence I=V/R which means that when the supply voltage is constant ,current is inversely proportional to resistance.thus the current doubles. practically speaking when the resistance of the load(fan ,bulb,refrigerator,....) is less ,it draws more current from the source so as to balance the voltage across it.i.e; to maintain the voltage across it as constant. This answer is absolutely correct if you assume that the current comes from a pure voltage source ( voltage source with zero internal resistance). At the other extreme you could have a current source (such as a very large voltage source in series with a very large resistor), and then the current is practically independent of changes if the external resistance is changed (because the change represents a relatively minute change in the overall resistance). With appropriate circuitry it is possible to devise a situation where the current is practically independent of the changing resistance.

Impedance of a coil or a capacitor does depend on the excitation frequency,but resistance has no relationship to frequency.

Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases

When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.