Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.
Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
Ohm's Law: Current is voltage divided by resistance, so doubling voltage while holding resistance constant will double current.
Not asked, but answered for completeness sake; since power is voltage times current, doubling the voltage while holding the resistance constant will quadruple the power.
Since V=I*R
R=V/I
IF R=2V/I, R is twice as big
the question has limited information, if circuit is single resistsnce circuit than voltage will remain same as supply even if we change the resistence.
Providing the voltage remains constant, doubling a circuit's resistance will halve the amount of current.
If current doubles, the power dissipated by a resistor quadruples.
If the voltage remains constant then the current is reduced by 1/2.
ambot
It isn't. If you're using superposition, you open circuit current sources and short voltage sources; this is because the current source declares the current that will be flowing through that branch. Both current and voltage sources have a finite internal resistance.
The net resistance can be found out using the algebraic sums f series and parallel connections. When there is no current flowing in the circuit the net resistance is infinite.
Here is the formula you use. I = E/R. I = amperage, E = volts, R = resistance in ohms.
we can calculate the current in a commmon electrical circuit by this formulae i.e,I=V\R where i is the current flowing in the conductor, R is resistance , V is the voltage.. THE FORMULA IS CORRECT but the term conductor does not suffice an explanation since a conductor is low in resistance R= resistance not conduction.
Resistance
When the current flowing in a circuit is very small the resistance will be very high.
The resistance of the circuit will be 46 ohms
lowers the amt of electrical current flowing through it.
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
Depends - in the real world as a resistor gets hotter (current flowing through it) its resistance increases.
With the same voltage and resistance the current will be the same value.
It isn't. If you're using superposition, you open circuit current sources and short voltage sources; this is because the current source declares the current that will be flowing through that branch. Both current and voltage sources have a finite internal resistance.
The net resistance can be found out using the algebraic sums f series and parallel connections. When there is no current flowing in the circuit the net resistance is infinite.
..using the formula Voltage(V)=Current(I) * Resistance(R) .. we can get the result ...current will be 5 Ampere
It depends on the resistance (or impedance) of that branch alone.
An ammeter has to measure to current flowing through the circuit. Resistance offers an obstruction to the current flow. So, if the resistance of an ammeter is large , the current measured by the ammeter will be quite less as compared to the actual amount of current flowing through the circuit which is undesirable. If ammeter has zero resistance , then it will give the exact value of current. But this is not practically possible because every material has some value of internal resistance which we can't control. For this reason , ammeter must have small resistance
This is called a closed circuit. If current was not flowing, it would be open.