since Barium is a metal in group 2 of the Periodic Table, that means it has two electrons in its outer shell. Dont ask me why, it's how scientists arranged it, the atoms who have 2 valency electrons are grouped together, the ones with 3 are grouped together and so on..Anyway, Barium is a group 2 metal, which means when it reacts with a non-metal it will give away those two electrons to the non-metal. now you must know that the number of electrons are equal to the number of protons , right? well they are. so when it reacts and gives its electrons away, the atom becomes two electrons less AND the protons are more than the number of electrons by 2, so the atom becomes POSITIV by two!
Barium has 56 electrons and protons, so when it reacts, it looses the two valency electrons and gains the positive charge of +2!
so the final answer for your question is Ba+2
that wasnt so bad
Write an equation that shows the formation of a strontium ion from a neutral strontium atom.
Represent electrons as e-.
If a box is not needed, leave it blank.
Correct answer:
Sr
Sr
Your response:
Sr
+
Correct answer:
Your response:
2 e-
Correct answer:
Sr2+
Sr^2+^
Your response:
Sr2+
+
Correct answer:
2 e-
2 e^-^
Your response:
Since potassium is a metal in group 1A it is expected to form a positive ion (a cation) with the magnitude of the charge equal to the group number. The charge is therefore +1.
The symbol for the potassium ion is therefore K+ ----K++e-
K has an atomic number of 19, with 19 protons and 19 electrons in the neutral atom. In order for the ion to carry a charge of +1 it must have 1 more proton than it does electrons, so the atom must lose 1 electron.
The equation that shows the ion forming from the neutral atom is therefore: K K+ + e-
Note that chemical equations are always written 'left side' turns into 'right side'. The neutral K atom turns into a K+ ion and 1 electron.
Barium ions are formed by means of the decomposion of barium-EDTA complex with hydrogen peroxide in the presence of sulfate
study really hard and maybe you can get :P
The chemical equation that shows the formation of a cesium ion from a neutral cesium atom is:Cs (g) --------------> Cs+1 (g) + e-
Ba, Ba^2+^, 2e^-^ = Ba, Ba2+, 2e-
2Cs + I2 = 2CsI
Caesium----------------Caesium+ + e-
Ba2+
The reaction between cesium and water is explosive. Refer the the related link below to see examples of cesium, including a videoclip of cesium in water. 2Cs + 2H2O ---> 2CsOH + H2
3CsOH(aq) + H3PO4(aq) --> Cs3PO4(aq) + 3H2O(l)
Cesium hydrogen carbonate is CsHCO3
Formula: CsI
They form cesium sulfide, and the formula is Ce2S.
Cesium acetate would be mildly basic as the cesium ion is neutral while the acetate ion is a weak base.
The reaction between cesium and water is explosive. Refer the the related link below to see examples of cesium, including a videoclip of cesium in water. 2Cs + 2H2O ---> 2CsOH + H2
The chemical name for cesium bromate is cesium bromate. The chemcial formula for cesium bromate is CsBrO3, and its CAS number is 13454-75-6
Cesium bicarbonate would be CsHCO3
3CsOH(aq) + H3PO4(aq) --> Cs3PO4(aq) + 3H2O(l)
Cesium hydrogen carbonate is CsHCO3
what are the products of the reaction between aluminum chloride and cesium
Formula: CsI
Cesium (the chemical element Cs) was discovered by Bunsen and Kirchoff in 1860.
Name: Cesium IodideEmpirical formula: CsIIonic Formula: CS1I1
They form cesium sulfide, and the formula is Ce2S.
Cs3N is cesium nitride.