It os burning with oxygen.Products are water and CO2
MEthane or CH4 with complete combustion will turn into CO2 and H2O The formula for complete combustion of methane: CH4 + 2O2-> CO2 + 2H2O
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
Incomplete combustion of Methane is....2CH4 + 2O2 --> CO + C + 4H2O
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Hydrocarbons such as methane burning in oxygen is an example of oxidation and also combustion.
MEthane or CH4 with complete combustion will turn into CO2 and H2O The formula for complete combustion of methane: CH4 + 2O2-> CO2 + 2H2O
Hydrogen combines with oxygen at the completion of a combustion reaction to form water. The following is the balanced equation for the combustion of methane (CH4). CH4 + 2O2 ---> CO2 + 2H2O
Ch4+2o2--->co2+2h2o+heat
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
Incomplete combustion of Methane is....2CH4 + 2O2 --> CO + C + 4H2O
A combustion reaction is a reaction that burns. The equation that represents a combustion reaction is CH4 + 2O2 reacts to yield CO2 + 2H2O.
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methane+oxyen-->carbon dioxide+waste CH4 O2 CO2 H2O
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
The reactants are CH4, O2 and the products are CO2, H2O. CH4 + 2O2 -> CO2 + 2H2O
A combustion reaction.