The power consumption of the motor cannot be determined without more information. The power consumption of any load can be determined with any two of three interrelated parameters--voltage, current, or load impedance. (Ohm's Law)
1 hp = about 745 watts
Therefore 250HP = 745 * 250 = 186250 Watts = about 186kW
CommentRemember that this is the output power of the motor. Its input power will need to be greater, to allow for the machine's efficiency.
Could be a single phase induction motor of 20-40 watts.
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?
To answer this question a voltage must be stated. W = A x V x pf.
The formula you are looking for is, kW x 1000/1.73 x volts x pf (power factor).
It should me stamped on the information plate. If this is not on it, then there will be the running current stamped on the plate. Multiply this by the supply voltage to find the power in watts. Take the horsepower of the motor and multiply it by 746. There are 746 watts in 1 HP. It is also the same for single phase motors.
Could be a single phase induction motor of 20-40 watts.
317.025280 KILOWATTS = 317,025.28 WATTS
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
To answer this question the voltage of the motor must be given. Watts is the product of amps x volts. Amps = Watts/Volts. Once this is found the motor breaker needs to be larger to allow for the inrush start current.
To answer this question, the voltage whether the supply is single or three phase, of the 1.5 HP motor must be given.
Low-power (a few watts) might use a synchronous motor, most fans use an induction motor. Above a couple of horse-power it might be a 3-phase induction motor.
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?
To answer this question a voltage must be stated. W = A x V x pf.
They are the same and they use a singe-phase induction motor of 15-30 watts
The formula you are looking for is, kW x 1000/1.73 x volts x pf (power factor).
As watts are made of volts times amps, the answer would be 0.660kw.