What is the c program to count the no of digits in the given number in proper formatted way?

Answer 1

Repeatedly divide by the base until the number is 0, counting the number of divisions as you go.

int count_digits (int n, int base=10) { // default to decimal notation

if (base<2) {/* handle invalid argument */}

int count=0;

while (n!=0) {

n/=base;

++count;

}

return count;

}

Note that the value 0 has no digits. If you wish to count 0 as a digit, alter the algorithm as follows:

int count_digits (int n, int base=10) { // default to decimal notation if (base<2) {/* handle invalid argument */}

int count=0;

do {

n/=base;

++count;

} while (n!=0);

return count;

}