Na3 PO4 + Ba (NO3)2 Þ Ba3 (PO4)2 + Na NO3 Balance Equation: Na= 3 6 ÞNa= 1 6 P= 1 2 ÞP=2 O= 10 18 22 26 ÞO= 11 26 Ba= 1 3 ÞBa=3 N= 2 6 ÞN= 1 6 Na3 PO4 + Ba (NO3)2 Þ Ba3 (PO4)2 + Na NO3 Na3 PO4 + 3Ba (NO3)2 Þ Ba3 (PO4)2 +Na NO3 Na3 PO4 + 3Ba (NO3)2 Þ Ba3 (PO4)2 +6Na NO3 2Na3 PO4 + 3Ba (NO3)2 Þ Ba3 (PO4)2 +6Na NO3
2NaCl(aq) + Ba(NO3)2(aq) ==> 2NaNO3(aq) + BaCl2(s)
The chemical equation is:
Ba(NO3)2 + Na2SO4 = BaSO4 (s) + 2 NaNO3
The chemical equation is:
Ba(NO3)2 + 2 NaHCO3 = 2 NaNO3 + Ba(HCO3)2
Al2(SO4)3 + 3BaCl2 yeilds 2AlCl3 + 3BaSO4
Double Replacement Reaction.
Any reaction occur.
Strontium Nitrate: Sr(NO3)2Potassium Phosphate: K3PO4
nigggers
Do you want that for Monopotassium phosphate, dipotassium phosphate, or tripotassium phosphate? --------------------------------- To clarify for the previous answerer, ionic compounds inherently don't use the mono-, di-, or tri- system used for molecular compounds. Instead, when a cation and an anion is supplied, the ionic compound assumes the number of cations and anions that will generate a neutral ionic compound. In this case, since K is 1+ and PO4 is 3-, the compound potassium phosphate always refers to K3PO4. Therefore: 3AgNO3 + K3PO4 -> 3KNO3 + Ag3PO4
2KNO3 (s) ==heat==> 2KNO2(s) + O2(g) potassium nitrate decomposes to potassium nitrite and oxygen. NB Note the spelling for the product.
The balanced equation is: Zn(C2H3O2)2 + NaPO4 --> ZnPO4 + Na(C2H3O2)2.
Strontium Nitrate: Sr(NO3)2Potassium Phosphate: K3PO4
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
nigggers
It is impossible to balance that equation.
Do you want that for Monopotassium phosphate, dipotassium phosphate, or tripotassium phosphate? --------------------------------- To clarify for the previous answerer, ionic compounds inherently don't use the mono-, di-, or tri- system used for molecular compounds. Instead, when a cation and an anion is supplied, the ionic compound assumes the number of cations and anions that will generate a neutral ionic compound. In this case, since K is 1+ and PO4 is 3-, the compound potassium phosphate always refers to K3PO4. Therefore: 3AgNO3 + K3PO4 -> 3KNO3 + Ag3PO4
2KNO3 (s) ==heat==> 2KNO2(s) + O2(g) potassium nitrate decomposes to potassium nitrite and oxygen. NB Note the spelling for the product.
The balanced equation is: Zn(C2H3O2)2 + NaPO4 --> ZnPO4 + Na(C2H3O2)2.
2Na3PO4 + 3Ca(NO3)2 --> 6NaNO3 + Ca3(PO4)2
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
Silver phosphate, Ag3PO4 precipitated in potassium nitrate solution (K+ and NO3-)
Kn2 heat equal kn2+o2
Pb(NO3)2 + 2KCl ---> PbCl2 + 2KNO3