The domain is from negative infinity to positive infinity.
The range is from positive 2 to positive infinity.
x2+2x+1=y or y=x2 In this function the domain is x equals real values and the range is y equals all real values provided y is more than or equal to zero.
Give the domain for
It is a quadratic function which represents a parabola.
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
x2+2x+1=y or y=x2 In this function the domain is x equals real values and the range is y equals all real values provided y is more than or equal to zero.
Give the domain for
It is a quadratic function which represents a parabola.
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
The range depends on the domain, which is not specified.
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
Assuming the domain and range are suitably defined, then yes. If not, then no.
The domain of a function is the set of it's possible x values that will make the function work and output y values. In this case, it would be all the real numbers.
The function is a simple linear function and so its nature does not limit the domain or range in any way. So the domain and range can be the whole of the real numbers. If the domain is a proper subset of that then the range must be defined accordingly. Similarly, if the range is known then the appropriate domain needs to be defined.
The domain can be anything you like: a single element, all real numbers, all complex numbers, etc.
A cubic function, continuous, differentiable.