The reactants are C8H18 and oxygen.
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
2 of octane react with 25 of oxygen so 12.5 moles of O2 react with 1 mole of C8H18.
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
9,846 g of tin (Sn)
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
K2SO4 + Pbl2 are the reactants.
The HCl is hydrochloric acid
2 of octane react with 25 of oxygen so 12.5 moles of O2 react with 1 mole of C8H18.
Copper sulfate is a reactant in the equation as stated, because it is present before the reaction has occurred and no longer present afterward.
3
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
There is no limiting reactant in that equation, it's balanced. Four hydrogens on the left, 4 on the right, 2 oxygens on the left, 2 oxygens on the right. If it was 3H2 then it would be oxygen.
Well, I'm not entirely sure what you're asking. In this reaction equation: Ba + ZnSO4 --> BaSO4 + Zn, barium is a reactant. The equation is balanced as is, so everything is in a nice even 1-to-1 molar ratio, making stoichiometric calculations pretty easy. That's about all I can tell you though, based on the limited information present.
8 daddy
There is no limiting reactant in that equation, it's balanced. Four hydrogens on the left, 4 on the right, 2 oxygens on the left, 2 oxygens on the right. If it was 3H2 then it would be oxygen.